Record the volume of the liquid in the graduated cylinder. The volume of the liquid is
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The molecular weight of the molecular compound is
x= 105.57 g/mol
<h3>What is the molecular weight of the molecular compound?</h3>Generally,a the equation for Mole of molecular compound is mathematically given as
Mm= mass / molar mass
Therefore
Mm= 0.333 g / x
the equation for Morality
M = mole of solute / mass of solvent
M= 10 / x
the equation for change in temp dt
dt= K* morality
Therefore
x = (5.12 *10) / 0.485
x = 105.57 g/mol
In conclusion, molecular mass of molecular compound
x= 105.57 g/mol
Read more about molecular compound
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The amount of CO that would be required to generate 635 g of CO2 will be 404.14 g
<h3>Stoichiometric problem</h3>First, let us get the equation of the reaction:
From the equation, we can see that the mole ratio of CO to that of CO2 is 1:1.
635 g of CO2 is to be generated.
Mole of 635 g CO2 = mass/molar mass = 635/44.01 = 14.43 moles
Thus, the equivalent mole of CO required will also be 14.43 moles.
Mass of 14.43 moles CO = moles x molar mass = 14.43 x 28.01 = 404.14 g
Hence, 404.14 g of CO will be required to produce 635 g of CO2
More on stoichiometric problems can be found here: brainly.com/question/14465605
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