Jim’s sleeping bag is 5 feet long.Jorge’ sleeping bag is 2 yards.Stevens sleeping bag is 68 inches,Whose sleeping bag is longer
1 answer:
You might be interested in
For this problem you are going to need to know the point-slope equation which is:
y-y₁=m(x-x₁)
Now, m=slope and the x and y values are given to us already, so now we just plug our variables into the formula.
It should look like this:
Since all they are asking for is for you to put it into a formula this will be your answer.
y-y₁=m(x-x₁)
Now, m=slope and the x and y values are given to us already, so now we just plug our variables into the formula.
It should look like this:
Since all they are asking for is for you to put it into a formula this will be your answer.
Answer:
a)
USL = 6.2 inches
LSL = 5.8 inches
b) Cp = 1.33
Cpk = 0.67
c)
Yes it meets all specifications
Step-by-step explanation:
The specification for a plastic handle calls for a length of 6.0 inches ± .2 inches. The standard deviation of the process is estimated to be 0.05 inches. What are the upper and lower specification limits for this product? The process is known to operate at a mean thickness of 6.1 inches. What is the Cp and Cpk for this process? Is this process capable of producing the desired part?
Given that:
Mean (μ) = 6.1 inches, Standard deviation (σ) = 0.05 inches and the length of the plastic handle is 6.0 inches ± .2
a) Since the length of the plastic handle is 6.0 inches ± .2 = (6 - 0.2, 6 + 0.2)
The Upper specification limits (USL) = 6 inches + 0.2 inches = 6.2 inches
The lower specification limits (LSL) = 6 inches - 0.2 inches = 5.8 inches
b) The Cp is given by the formula:
The Cpk is given by the formula:
c)
The upper specification limit lies about 3 standard deviations from the centerline, and the lower specification limit is further away, so practically all units will meet specifications