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NeTakaya
3 years ago
5

Jim’s sleeping bag is 5 feet long.Jorge’ sleeping bag is 2 yards.Stevens sleeping bag is 68 inches,Whose sleeping bag is longer

Mathematics
1 answer:
Mariulka [41]3 years ago
4 0

Well, we know 1 yard is 3 feet, so 2 yards is 6 feet. That makes Jorge's sleeping bag longer than Jim's. (6 feet is longer than 5 feet)

We also know that 1 yard is 36 inches, so 2 yards is 72 inches. That makes Jorge's sleeping bag longer than Steven's. (72 inches is longer than 68 inches)

Since Jorge's sleeping bag is longer than both Jim's and Steven's, Jorge's sleeping bag is longer.

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Which statement describes this system of equations? 9x – 6y = 15, 3x – 2y = 5 The equations in the system are equivalent equatio
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Answer:

There is no solution to the systems of equation.

Step-by-step explanation:

Graph the system by using y=mx+b

Both systems are y=2/5x+5/2.

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c^2( c^2-10c+25)

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Estimate the area of a circle with a radius of 3.1 feet
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Step-by-step explanation:

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Expon
Tema [17]

A and D , that is, 5∛2x and -3∛2x are sets of the radical expressions listed that could be considered like terms. This can be obtained by understanding what like radicals are.

<h3>Which sets of the radical expressions listed could be considered like terms as written?</h3>
  • Radical expression: Radical expression is an equation that has a variable in a radicand (expression under the root) or has a variable with a rational exponent.

For example, √128, √16

  • Like radicals: Radicals that have the same root number and radicand (expression under the root)

For example, 2√x and 5√x are like terms.

Here in the question radical expressions are given,

  • 5∛2x
  • -4x∛2
  • 5√2x
  • -3∛2x
  • 5x√2x

By definition of like radicals we get that 5∛2x and -3∛2x are like terms since root number and radicand are same, that is, root number is 3 and radicand is 2x.

Hence A and D , that is, 5∛2x and -3∛2x are sets of the radical expressions listed that could be considered like terms.

Learn more about radicals here:

brainly.com/question/16181471  

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3 0
1 year ago
the cost of running an appliance varies jointly as the number of watts used, the hours of operation, and the cost per kilo-watt
zhuklara [117]
Suppose:
C=cost
c=cost per kilo-watt hour
w=number of watts
h=number of hours
thus
C=kwhc
where:
k=constant of proportionality:
k=C/(whc)
but
C=15 when w=6000, h=10/60=1/6 hours, c=7.5 cents per kw/h
thus
k=15/(6000*1/6*7.5)
k=0.002
thus:
C=0.002(whc)
hence:
when 
h=70*2=140=140/6=70/3 hours the cost will be:
C=0.002(6000*70/3*7.5)
C=2100 cents
C=$21

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