To solve any problem in math or physics, you collect all the formulas,
laws, rules, and equations that you know about the subject, then, along
with the given information, use them to find the missing information.
So the answer to "how" really depends on what information you're given.
B. the electron's energy changes.
Answer:
Lastly, the heat transfer rate depends on the material properties described by the coefficient of thermal conductivity. All four factors are included in a simple equation that was deduced from and is confirmed by experiments. The rate of conductive heat transfer through a slab of material, such as the one in Figure 3, is given by
Q
t
=
k
A
(
T
2
−
T
1
)
d
,
where
Q
t
is the rate of heat transfer in watts or kilocalories per second, k is the thermal conductivity of the material, A and d are its surface area and thickness, as shown in Figure 3, and (T2 − T1) is the temperature difference across the slab. Table 1 gives representative values of thermal conductivity.
Explanation:
Answer:
124.86 V
Explanation:
We have to first calculate the voltage drop across the copper wire. The copper wire has a length of 358 ft
1 ft = 0.3048 m
358 ft = 109.12 m
The diameter of 2 AWG copper wire (d) = 6.544 mm = 0.006544 m
The area of the wire = πd²/4 = (π × 6.544²)/4 = 33.6 mm²
Resistivity of wire (ρ) = 0.0171 Ω.mm²/m
The resistance of the wire =
The voltage drop across wire = current * resistance = 6.1 A * 0.056 ohm = 0.34 V
The voltage at end = 125.2 - 0.34 = 124.86 V
Answer:
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