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3 years ago

Which energy transformation occurs in the core of a nuclear reactor?

Physics

2 answers:

Nataliya [291]3 years ago

8 0

It's either A or B because it starts off as nuclear energy.

kondaur [170]3 years ago

6 0

its actually nuclear energy to thermal energy = (B)

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Light bulbs produce useful energy in the form of light and waste energy in the form of heat. What kind of light bulb would you u

Tatiana [17]

Answer:

C) high efficiency light bulbs, because they produce more heat

4 0

3 years ago

A centrifuge in a medical laboratory rotates at an

suter [353]

Answer:

- 273.77 rad/s^2

Explanation:

fo = 3800 rev/min = 3800 / 60 rps = 63.33 rps

f = 0

ωo = 2 π fo = 2 x 3.14 x 63.33 = 397.71 rad/s

ω = 2 π f = 0

θ = 46 revolutions = 46 x 2π radian = 288.88 radian

Let α be the angular acceleration of the centrifuge

Use third equation of motion for rotational motion

$\omega^{2}=\omega _{0}^{2}+2\alpha \theta$

$0^{2}=397.71^{2}+2 \times \alpha \times 288.88$

α = - 273.77 rad/s^2

4 0

3 years ago

A magnetic field has a magnitude of 0.078 T and is uniform over a circular surface whose radius is 0.10 m. The field is oriented

oee [108]

Answer:

Magnetic flux, $\phi=2.22\times 10^{-3}\ Wb$

Explanation:

It is given that,

Magnitude of the magnetic field, B = 0.078 T

Radius of circular loop, r = 0.1 m

The field is oriented at an angle of θ = 25° with respect to the normal to the surface. The magnetic flux through the surface is given by :

$\phi=BA\ cos\theta$

$\phi=0.078\times \pi \times (0.1)^2\ cos(25)$

$\phi=0.00222\ Wb$

$\phi=2.22\times 10^{-3}\ Wb$

So, the magnitude of magnetic flux through the surface is $2.22\times 10^{-3}\ Wb$ . Hence, this is the required solution.

4 0

3 years ago

Suppose that there are N=108 two-state systems, each with energy difference E=6 × 10-21 J between the two states. The environmen

kati45 [8]

Answer:

The value of $\dfrac{dU}{dM}$ is $6\times10^{-29}\ J/unit$ .

Explanation:

Given that,

Number $N=10^{8}$

Energy difference = 6\times10^{-21}\ J[/tex]

Temperature T =300 K

We need to calculate the value of $\dfrac{dU}{dM}$

We know that,

$\dfrac{dU}{dM}=\dfrac{energy\ difference}{Change\ in\ number\ of\ system}$

$\dfrac{dU}{dM}=\dfrac{6\times10^{-21}}{10^{8}}$

$\dfrac{dU}{dM}=6\times10^{-29}\ J/unit$

Hence, The value of $\dfrac{dU}{dM}$ is $6\times10^{-29}\ J/unit$ .

5 0

4 years ago

How does Newton's second law of motion can be used to calculate the acceleration of an object?

Alex777 [14]

Newton's second law of motion can be formally stated as follows: The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.

4 0

4 years ago