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valina [46]
1 year ago
10

Safety belts and occupant protection systems are installed to reduce the harmful effects of the force of _____ during a collisio

n.
Physics
1 answer:
Phantasy [73]1 year ago
3 0

To lessen the negative impacts of the force generated during a collision, safety belts and occupant protective relays are installed.

Importance of safety belts:

  • The purpose of a seat belt usually referred to as a safety belt or a safety belt, is to protect the driver or an occupant of a vehicle from a potentially dangerous movement that may occur during an accident or an abrupt stop. By minimizing the power of secondary hits with interior striking hazards, maintaining proper occupant positioning for the airbag, and preventing people from being expelled from the vehicle after an accident or if the automobile rolls over, seat belts help minimize the chance of a fatal accident in traffic collisions. When the car is moving, the passenger and the driver move together with it at the same pace.
  • The occupants continue moving at the same pace the vehicle was traveling at when it stopped if it unexpectedly stops or crashes. To stop the driver and other passengers from exiting the vehicle or contacting the interiors of the vehicle, seatbelts apply an equal and opposite force to them. Due to their crucial function in occupant safety, seatbelts are regarded as the main restraint devices.

Learn more about safety belts here:

brainly.com/question/5626690

#SPJ4

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Answer:

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5 0
3 years ago
A 4.80 −kg ball is dropped from a height of 15.0 m above one end of a uniform bar that pivots at its center. The bar has mass 7.
Margarita [4]

Answer:

h = 13.3 m

Explanation:

Given:-

- The mass of ball, mb = 4.80 kg

- The mass of bar, ml = 7.0 kg

- The height from which ball dropped, H = 15.0 m

- The length of bar, L = 6.0 m

- The mass at other end of bar, mo = 5.10 kg

Find:-

The dropped ball sticks to the bar after the collision.How high will the other ball go after the collision?

Solution:-

- Consider the three masses ( 2 balls and bar ) as a system. There are no extra unbalanced forces acting on this system. We can isolate the system and apply the principle of conservation of angular momentum. The axis at the center of the bar:

- The angular momentum for ball dropped before collision ( M1 ):

                                 M1 = mb*vb*(L/2)

Where, vb is the speed of the ball on impact:

- The speed of the ball at the point of collision can be determined by using the principle of conservation of energy:

                                  ΔP.E = ΔK.E

                                  mb*g*H = 0.5*mb*vb^2

                                  vb = √2*g*H

                                  vb = ( 2*9.81*15 ) ^0.5

                                  vb = 17.15517 m/s

- The angular momentum of system before collision is:

                                  M1 = ( 4.80 ) * ( 17.15517 ) * ( 6/2)

                                  M1 = 247.034448 kgm^2 /s

- After collision, the momentum is transferred to the other ball. The momentum after collision is:

                                  M2 = mo*vo*(L/2)

- From principle of conservation of angular momentum the initial and final angular momentum remains the same.

                                 M1 = M2

                                 vo = 247.03448 / (5.10*3)

                                 vo = 16.14604 m/s

- The speed of the other ball after collision is (vo), the maximum height can be determined by using the principle of conservation of energy:

                                  ΔP.E = ΔK.E

                                  mo*g*h = 0.5*mo*vo^2

                                  h = vo^2 / 2*g

                                  h = 16.14604^2 / 2*(9.81)

                                  h = 13.3 m

3 0
3 years ago
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Alina [70]

Answer:

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Explanation:

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Answer:

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Explanation:

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