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mestny [16]
3 years ago
6

Limit question please?

Mathematics
1 answer:
Ksivusya [100]3 years ago
7 0
The easiest way to evaluate the limit is to simply subsitute the value into the function

as x approaches -3
just subsitute -3 for x

(-3)³=(-3)(-3)(-3)=-27
answer is -27
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Gabriel divides 64 grapes among his 15 friends. How many grapes does Gabriel give each friend?
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3 years ago
Evaluate the expression. –5g – 6 for g = –2
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4

Step-by-step explanation:

Given that:

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On a morning of a day when the sun will pass directly​ overhead, the shadow of a 60​-ft building on level ground is 25 ft long.
AysviL [449]

Answer:

The shadow is decreasing at the rate of 3.55 inch/min

Step-by-step explanation:

The height of the building = 60ft

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Ѳ is increasing at the rate of 0.24°/min

Using SOHCAHTOA,

Tan Ѳ = opposite/ adjacent

= height of the building / length of the shadow

Tan Ѳ = h/x

X= h/tan Ѳ

Recall that tan Ѳ = sin Ѳ/cos Ѳ

X= h/x (sin Ѳ/cos Ѳ)

Differentiate with respect to t

dx/dt = (-h/sin²Ѳ)dѲ/dt

When x= 25ft

tanѲ = h/x

= 60/25

Ѳ= tan^-1(60/25)

= 67.38°

dѲ/dt= 0.24°/min

Convert the height in ft to inches

1 ft = 12 inches

Therefore, 60ft = 60*12

= 720 inches

Convert degree/min to radian/min

1°= 0.0175radian

Therefore, 0.24° = 0.24 * 0.0175

= 0.0042 radian/min

Recall that

dx/dt = (-h/sin²Ѳ)dѲ/dt

= (-720/sin²(67.38))*0.0042

= (-720/0.8521)*0.0042

-3.55 inch/min

Therefore, the rate at which the length of the shadow of the building decreases is 3.55 inches/min

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3 years ago
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jolli1 [7]

Answer:

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Step-by-step explanation:

7 0
3 years ago
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