Since the Area of a Triangle is Base * Height then the formula should be: A = BH 20 = H(2+2H) 20 = 2H^2 + 2H 0 = 2H^2 + 2H - 20
Find the zeros of the quadratic equation through substituting the values of a,b, and c. You will get the zeros of x = 2.7 and -3.7. The only thing that would make sense is you use the x=2.7 because there are no negative heights.
Since b = 2h+2 b= 2(2.7) + 2 b= 5.4 + 2 b=7.4
I don't know where you got 4 and 10, but what I got is different.