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julia-pushkina [17]
3 years ago
10

The base of a triangle is 2 more than twice the height of the triangle. Find the measure of the base and the height if the area

is 20 ft^2 (the height is 4 and the base is 10, show a process so I can see how you got there
Mathematics
1 answer:
vekshin13 years ago
8 0
B = 2 + 2H 
A = 20 ft^2
H = H

Since the Area of a Triangle is Base * Height then the formula should be:
A = BH
20 = H(2+2H)
20 = 2H^2 + 2H
0 = 2H^2 + 2H - 20 

Find the zeros of the quadratic equation through substituting the values of a,b, and c. You will get the zeros of x = 2.7 and -3.7. The only thing that would make sense is you use the x=2.7 because there are no negative heights.

Since b = 2h+2 
b= 2(2.7) + 2
b= 5.4 + 2 
b=7.4

I don't know where you got 4 and 10, but what I got is different. 
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the area of a trapezoid is 21 inches, one of its bases is 8 inches and its height is 3 inches. What is the length of the last ba
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3 0
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Solve each equation. Record your work and check your solution. <br> a. 5(x-2)+(-9)= -7(1-x)
Daniel [21]

The solution for equation is x = -6

<em><u>Solution:</u></em>

<em><u>Given equation is:</u></em>

5(x-2) + (-9) = -7(1-x)

We have to solve the equation

According to Bodmas rule, if an expression contains brackets ((), {}, []) we have to first solve or simplify the bracket followed by of (powers and roots etc.), then division, multiplication, addition and subtraction from left to right

Therefore, solve for brackets in given equation

5(x-2) + (-9) = -7(1-x)\\\\5x - 10 -9 = -7 + 7x

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Move the variables to one side and constants to other side

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