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NNADVOKAT [17]
3 years ago
12

01

Chemistry
2 answers:
m_a_m_a [10]3 years ago
6 0

Answer:

The correct answer is -  Positive charge occupies a very small volume in the atom.

Explanation:

Ernest Rutherford's experiments exhibited the presence of the nuclear core: a small region with the greater part of the mass of the atom and the positive charge.  

Rutherford's gold foil analyze gave three conclusions:  

- the particle is generally vacant space  

- in it is a little, thick core  or dense nucleus

- the core is positively charged.

Aleksandr-060686 [28]3 years ago
6 0

Answer:

d

Explanation:

Just tested on edge

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C. the number of protons and neutrons an element has in its nucleus
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Adding sugar to your tea physical or chemical change ​
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physical

Explanation:

no chemical reaction occurs

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For the cell constructed from the hydrogen electrode and metal-insoluble salt electrode, B) calculate the mean activity coeffici
Brut [27]

<u>Question:</u>

For the cell constructed from the hydrogen electrode and metal-insoluble salt electrode, B) calculate the mean activity coefficient for 0.124 b HCl solution if E=0.342 V at 298 K

<u>Answer:</u>

The mean activity coefficient for HCl solution is 0.78.

<u>Explanation:</u>

Activity coefficient is defined as the ratio of any chemical activity of any substance with its molar concentration. So in an electrochemical cell, we can write activity coefficient as γ. The equation for determining the mean activity coefficient is

              E=E_{0}-0.0514 \mathrm{V} \ln \gamma

As we know that E_{0} = 0.22 V and E = 0.342 V, the equation will become

             0.342 V+0.0514 V \ln (0.124)=0.22 V-0.0514 V \ln \gamma

             0.342 V-0.222 V=-0.0514 V(\ln \gamma+\ln 0.124)

             0.12 \mathrm{V}=-0.0514 \mathrm{V}(\ln \gamma+\ln 0.124)

             \frac{0.12}{0.0514}=-\ln (0.124 \gamma)

             -2.3346=\ln (0.124 \gamma)

             e^{-2.3346}=0.124 \gamma

             0.0968=0.124 \gamma

             \gamma=\frac{0.0968}{0.124}=0.78

So, the mean activity coefficient is 0.78.

6 0
3 years ago
how many grams of phosphorus (P4) react with 35.5L of O2 at STP to form solid tetraphosphorus decaoxide
algol [13]

Answer:

mass P4 = 35.998 g

Explanation:

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∴ STP: P = 1 atm; T = 298 K

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⇒ nO2 = P.V / R.T

∴ R = 0.082 atm.L/K.mol

⇒ nO2 = ((1 atm)×(35.5L))/((0.082 atm.L/K.mol)(298K))

⇒ nO2 = 1.453 mol O2

⇒ mol P4 = (1.453 molO2)×(mol P4/ 5molO2) = 0.2906 mol P4

∴ Mw P4 = 123.895 g/mol

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How many pints are in a 48 cups?
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HOPE THIS HELPED
:)
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