Answer:
81 L gas
General Formulas and Concepts:
<u>Ideal Gas Law</u>
- STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K
<u>Stoichiometry</u>
- Using Dimensional Analysis
Explanation:
<u>Step 1: Define</u>
[Given] 3.6 mols gas at STP
[Solve] volume (L) of gas
<u>Step 2: Convert</u>
- [DA] Set up:

- [DA] Multiply [Cancel out units]:

<u>Step 3: Check</u>
<em>Follow sig fig rules and round. We are given 2 sig figs.</em>
80.64 L gas ≈ 81 L gas
Missing question: <span>A 5.00 L sample of O2 at a given temperature and pressure contains a 1.08x10^23 molecules. How many molecules would be contained in each of the following at the same temperature and pressure? </span>
a) 5.00 L H2.
<span>b) 5.00 L CO2.
Use </span>Avogadro's Law: The Volume Amount Law: <span>equal </span>volumes<span> of all gases, at the same temperature and pressure, have the same </span>number<span> of molecules. Because hydrogen and carbon(IV) oxide are gases, number of molecules are the same as number of oxygen molecules, so:
a) N(H</span>₂) = 1.08·10²³.
b) N(CO₂) = 1.08·10²³
It is the chlorophyll/chloroplast. The chlorophyll is the color
C. Shape, because increasing pressure has a profound influence on the volume of a gas sample, for example, it pushes the particles closer together; thus gases are considered compressible.