Question

A primary job of team management is to manage player salaries so that productive players make more than others. This serves the purpose of rewarding players and providing incentives. For defensive backs, bonuses are given for interceptions. Each interception earns a player $25,000. If Ken makes $600,000 in salary and gets seven interceptions per year, what is the percentage increase in his overall pay? (Round to the nearest percentage.)

Answer 1

Answer: 29%

Step-by-step explanation:

Given : The annual salary of Ken = $600,000

The number of interceptions earned by her = 7

Each interception value = $25,000

Therefore, total money added to her income =$7\times25,000=\ 175,000$

Now, the percentage increase in his overall pay is given by :-

$P=\frac{\text{change in income}}{\text{Salary}}\times100\\\\\Rightarrow P=\frac{175000}{600000}\times100=29.1666666667\approx29\%$

Hence,  the percentage increase in his overall pay is 29%.

Answer 2

Answer:

29%

Step-by-step explanation: