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3 years ago

I need some help on this if possible

Mathematics

1 answer:

Sophie [7]3 years ago

4 0

where C is the circumference, d is the diameter and r is the radius.

The diameter of a circle is a line segment that passes through the center of the circle and has its endpoints on the circle. The radius of the circle is a line segment from the center of the circle to a point on the circle. The diameter of a circle is twice the length of its radius.

If you are given the diameter then use the formula C = πd

If you are given the radius then use the formula C = 2πr

Step-by-step explanation:

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When solving the equation x2 – 8x - 7 = 0 by completing the square, which equation

IgorLugansk [536]

<h3>Answer:-</h3>

Lets Solve

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3 years ago

What is the b-value in the base exponential function stand for?

IrinaK [193]

Answer:

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3 years ago

Given y=3x - 4, write an equation that is shifted down 10 and is less steep.

antoniya [11.8K]

Answer:

y = ½x - 14

Step-by-step explanation:

Given the linear equation, y = 3x - 4, where the slope, m = 3, and the y-intercept is (0, -4):

The slope of a linear equation represents the steepness of the line's graph. The higher the value of the slope, the steeper the line. Hence, the slope of the other line must be less than three, but is greater than zero: 0 < m < 3. (a negative slope will show a declining line).

Next, the vertical translation of the line involves changing the value of the parent graph's y-intercept. Since the prompt states that the equation must represent a downward vertical shift of 10 units, then the y-intercept of the other line must be (0, -14).

The linear equation that I have chosen that meets the requirements of the given prompt is: y = ½x - 14. You're more than welcome to choose a different slope, as long as it is less than 3, but is greater than 0 (must be a positive slope).

Attached is a graph of both equations, to demonstrate that the other equation represents a graph with a steeper slope than the original graph.

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2 years ago

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Answer and explanation:

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LenKa [72]

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