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yawa3891 [41]
4 years ago
6

Rewrite y=x^2+6x+2 in vertex form​

Mathematics
1 answer:
Greeley [361]4 years ago
5 0

Answer:(x+3) 2−7

Step-by-step explanation:

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What is the length of a diagonal of a cube with a side length of 8 inches?
sashaice [31]

Answer:

13.9 inches

Step-by-step explanation:

Let the length of diagonal of cube be d inches.

\therefore \: d = length \: of \: side \sqrt{3}  \\ \hspace{16 pt}  = 8 \sqrt{3}  \\ \hspace{16 pt} =8 \times  1.73205081 \\ \hspace{16 pt} = 13.8564065 \\    \huge \red{ \boxed{\therefore \: d = 13.9 \: inches }}\\

8 0
3 years ago
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Let theta be an angle in quadrant II such that cos theta = -2/3
Iteru [2.4K]

Answer:

So we have \csc(\theta)=\frac{3 \sqrt{5}}{5} \text{ and } \tan(\theta)=\frac{-\sqrt{5}}{2}.

Step-by-step explanation:

Ok so we are in quadrant 2, that means sine is positive while cosine is negative.

We are given \cos(\theta)=\frac{-2}{3}(\frac{\text{adjacent}}{\text{hypotenuse}}).

So to find the opposite we will just use the Pythagorean Theorem.

a^2+b^2=c^2

(2)^2+b^2=(3)^2

4+b^2=9

b^2=5

b=\sqrt{5}  This is the opposite side.

Now to find \csc(\theta) and \tan(\theta).

\csc(\theta)=\frac{\text{hypotenuse}}{\text{opposite}}=\frac{3}{\sqrt{5}}.

Some teachers do not like the radical on bottom so we will rationalize the denominator by multiplying the numerator and denominator by sqrt(5).

So \csc(\theta)=\frac{3}{\sqrt{5}} \cdot \frac{\sqrt{5}}{\sqrt{5}}=\frac{3 \sqrt{5}}{5}.

And now \tan(\theta)=\frac{\text{opposite}}{\text{adjacent}}=\frac{\sqrt{5}}{-2}=\frac{-\sqrt{5}}{2}.

So we have \csc(\theta)=\frac{3 \sqrt{5}}{5} \text{ and } \tan(\theta)=\frac{-\sqrt{5}}{2}.

7 0
3 years ago
Read 2 more answers
??? Help me with my work pls
serious [3.7K]

Answer:

2. 10 + 5 x 2                    $20

3. 10 + 5 x 3                    $25

4. 10 + 5 x 4                    $30

Hope that helps!

Step-by-step explanation:

7 0
3 years ago
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Which statements are truth about exponential decay and functions ? Check all that apply
Alex787 [66]

there is not enough information

8 0
3 years ago
In FGH, the measure of H=90°, HF = 91 feet, and GH = 50 feet. Find the measure of F to the nearest degree.​
Nataly [62]

Answer:

28.8 degrees (rounded)

Step-by-step explanation:

you need to use tan^-1 in order to find x. tan is opposite side / adjacent side.

so...

tan^-1^(50/91) = 28.78661831

8 0
3 years ago
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