This one is so easy that your brain refuses to accept it.
It's looking for a harder answer, but can't find it !
You're totally correct, as far you went. x² + 2x does = -1
Now add ' 1 ' to each side: x² + 2x + 1 = 0
Can you factor that quadratic ?
Can you mash it through the quadratic formula ?
Actually, it's the simplest possible perfect square.
x² + 2x + 1 = (x + 1)²
So the solutions of x² + 2x + 1 = 0 are both x = -1 .
Don't say anything.
I know it's embarrassing.
Is this on a graph if so you need to explain futher
Answer:
7a-7
Step-by-step explanation:
2a+2−3a−5+a−4+7a.
Combine like terms
2a-3a+a+7a+2-5-4
7a-7
Let's say, the amount that each side was increased was "a"
so, it was 5 wide and 12 long, now it's 5+a wide and 12+a long
we know the area is 120, so whatever "a" is, we know that
(5+a)(12+a) = 120
so

use those factors, solve for "a"
Answer:
{ c ∣ c ≠ 2
, 12, -1, 0, c ∈ R }
Step-by-step explanation:
Considering the set

As we know that
- A function is said to be a relation if every x-value has one and only one y-value.
So, the value of c must not be equal to 2, 12, -1, 0 i.e. c ≠ 2, 12, -1, 0
Therefore,
{ c ∣ c ≠ 2
, 12, -1, 0, c ∈ R }