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4 years ago

What is the circumference. of the circle use 22/7 for piplease help :(

Mathematics

2 answers:

ZanzabumX [31]4 years ago

5 0

First, you need to multiply 2*21cm, which gives us 42 cm.

Then we multiply it by π, or 22/7 in this case, and 22/7*42cm gives us 132 cm.

So the answer is: 132cm.

Hope this helped! c:

Hitman42 [59]4 years ago

5 0

Answer:

B: 66

Step-by-step explanation:

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Write an expression in simplified form for the area of each rectangle. Width: 5+2y Length:5

Katena32 [7]

Answer:

25+10y

Step-by-step explanation:

The area of a rectangle is

A = l* w where l is the length and w is the width

A = 5(5+2y)

Distribute

A = 25+10y

7 0

3 years ago

Read 2 more answers

11, 15, 19,... Find the 46th term. WILL GET BRAINLIEST!!!!!!!!

mixer [17]

Answer:

191

Step-by-step explanation:

the rule is +4 so 11+45*4=191 (45 is the number not including the first one)

191 is the answer

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2 years ago

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At Royston's favorite clothing store, the cost of a pair of jeans is $4 more than twice the cost of a shirt. The cost of a pair

MrRa [10]

J(jeans) = 2s + 4
d(dress pants) = 2.5s - 2
s = shirt

he spent : 2s + 4 + 2.5s - 2 = 4.5s + 2

8 0

3 years ago

5x +4y=8 how do you transform that equation into Y=mx+b

Karolina [17]

1. subtract 5x on both sides

2. divide by 4 on both sides

Answer:

y= -5/4x + 2

7 0

3 years ago

The water content of a soil volume is measured four times gravimetrically by oven drying. The mean value of the water content is

expeople1 [14]

Answer:

99% confidence interval for the soil water content is determined by

(0.19474, 0.26926)

Step-by-step explanation:

Explanation:-

Given mean of the sample = 23.2% = 0.232

Given standard deviation of the sample = 1.0% =0.01

Given sample size 'n' =4

Degrees of freedom = n-1 =4-1 =3

critical value = 0.01

$t_{\frac{0.01}{2} } = t_{0.005} =7.4534$

99% confidence interval for the soil water content is determined by

$((x^{-} - t_{0.005} \frac{S.D}{\sqrt{n} } , (x^{-} + t_{0.005} \frac{S.D}{\sqrt{n} })$

$((0.232 - 7.4534\frac{0.01}{\sqrt{4} } , (0.232 + 7.4534 \frac{0.01}{\sqrt{4} })$

( 0.232 -0.03726 , 0.232 +0.03726)

(0.19474, 0.26926)

Final answer:-

99% confidence interval for the soil water content is determined by

(0.19474, 0.26926)

3 0

3 years ago