Answer:
- A) 290 km
- B) 4 hours
- C) 72.5 km/h
Step-by-step explanation:
Let distance be d and time t
<u>At 75 km/h speed the distance is</u>
- d = 75(t - 48 min) = 75(t - 48/60 hours)
<u>At 50 km/h speed the distance</u> is
<u>Since the distance is same, we get the equation:</u>
- 75(t - 48/60) = 50t + 40
- 75t - 75*4/5 = 50t + 40
- 75t - 60 = 50t + 40
- 75t - 50t = 40 + 60
- 25t = 100
- t = 4 hours
<u>A) The distance between A and B</u>
<u>B) Time is </u>
<u>C) The speed = d/t</u>
- Speed = 290/4 = 72.5 km/h
<span>Thomas rented 2 bicycles, which were late for return by 6 days. His fine for being late was 18$. If the fine for being late is count by multiplying the number of bicycles with the duration of the late, the answer would be:
fine = number of bicycle * duration of late
$18 =fine rate* 2 bicyles * 6 days
fine rate= (($18/ 2 bicyles) / 6 days) = $0.66 /bicycle days</span>
Answer: I think it is negative.
Step-by-step explanation: When you add a negative to a negative you still have a negative.
Answer:
Weights of at least 340.1 are in the highest 20%.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
a. Highest 20 percent
At least X
100-20 = 80
So X is the 80th percentile, which is X when Z has a pvalue of 0.8. So X when Z = 0.842.
Weights of at least 340.1 are in the highest 20%.
