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stiv31 [10]
4 years ago
13

What is ( √2 - √3 )² =

Mathematics
2 answers:
madreJ [45]4 years ago
7 0
2-2(square root of 6)+ 3
=5-2(square root of 6)
or 0.1
allochka39001 [22]4 years ago
4 0

just use FOIL (First, Outer, Inner, Last).

( √2 - √3 ) X ( √2 - √3 )

First: √2 X √2 = 2
Outer: √2 X -√3 = -√6
Inner: -√3 X √2 = -√6
Last: -√3 X -√3 = 3

and then add them together.

2 - √6 - √6 + 3
5 - 2(√6)

The answer is 5 - 2(√6) . 

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Please help with this math question thanks!!!
melisa1 [442]
The surface area is
A1=7.5*1.5*2=22.5 ft2 top and bottom view
A2=3*1.5*2=9 ft2 laterals view
A3=(7.5*1.5+2.5*1.5)*2=30 ft2  front and rear view

At=22.5+9+30=61.5 ft2
the answer is 61.5 ft2
5 0
3 years ago
Read 2 more answers
I need help with problem 1 with a through explanation and solution please <br><br>​
ki77a [65]

Explanation:

The cubic ...

  f(x) = ax³ +bx² +cx +d

has derivatives ...

  f'(x) = 3ax² +2bx +c

  f''(x) = 6ax +2b

<h3>a)</h3>

By definition, there will be a point of inflection where the second derivative is zero (changes sign). The second derivative is a linear equation in x, so can only have one zero. Since it is given that a≠0, we are assured that the line described by f''(x) will cross the x-axis at ...

  f''(x) = 0 = 6ax +2b   ⇒   x = -b/(3a)

The single point of inflection is at x = -b/(3a).

__

<h3>b)</h3>

The cubic will have a local extreme where the first derivative is zero and the second derivative is not zero. These will only occur when the discriminant of the first derivative quadratic is positive. Their location can be found by applying the quadratic formula to the first derivative.

  x=\dfrac{-2b\pm\sqrt{(2b)^2-4(3a)(c)}}{2(3a)} = \dfrac{-2b\pm\sqrt{4b^2-12ac}}{6a}\\\\x=\dfrac{-b\pm\sqrt{b^2-3ac}}{3a}\qquad\text{extreme point locations when $b^2>3ac$}

There will be zero or two local extremes. A local extreme cannot occur at the point of inflection, which is where the formula would tell you it is when there is only one.

__

<h3>c)</h3>

Part A tells you the point of inflection is at x= -b/(3a).

Part B tells you the midpoint of the local extremes is x = -b/(3a). (This is half the sum of the x-values of the extreme points.) You will notice these are the same point.

The extreme points are located symmetrically about their midpoint, so are located symmetrically about the point of inflection.

_____

Additional comment

There are other interesting features of cubics with two local extremes. The points where the horizontal tangents meet the graph, together with the point of inflection, have equally-spaced x-coordinates. The point of inflection is the midpoint, both horizontally and vertically, between the local extreme points.

6 0
3 years ago
Moving the decimal point to the right 4 places in a number is the same as _____. multiplying by 10 -4 multiplying by 4 multiplyi
faltersainse [42]

Answer:

10^4

Step-by-step explanation:

lets say the number is 1.0 if you where to move the decimal to the right 4 place the number would then be 10,000.0. basically if it says 10^4 add 4 0's

7 0
3 years ago
Read 2 more answers
If a diameter intersects a chord of a circle at a perpendicular, what conclusion can be made?
Agata [3.3K]

If a diameter intersects a chord of a circle at a perpendicular then the chord is bisected.

<h3>What is the relation between the chord and diameter of a circle?</h3>
  • The segments of a circle whose endpoints are on its perimeter are called chords.
  • A circle's diameter is the chord that passes across its center.
  • The circle's longest chord equals its diameter.
  • Any line that is perpendicular to a chord on the circle cuts it in half and goes through the center.

The solution to the problem:

A circle's chord is intersected perpendicularly by its diameter, which also passes through the center of the circle. The chord and diameter are perpendicular. Any line that is perpendicular to a chord on the circle and passes through its center divides it. The chord is divided equally by the diameter.

Therefore, the chord is bisected.

Learn more about diameter and chord at: brainly.com/question/12934647

#SPJ4

7 0
2 years ago
Can anyone help me out
Genrish500 [490]

Answer:

12k^5 +24k⁴+30k³

Step-by-step explanation:

the area = 6k³(2k²+4k+5)

= 12k^5 +24k⁴+30k³

5 0
3 years ago
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