A boy jogs 250 meters in 110 seconds. What is his average speed in m/s?
1 answer:
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We know that
to find the equation of a line i need two points
let
point A-----> (-21,10)
point B-----> (-28,14)
step 1
find the slope m
m=(y2-y1)/(x2-x1)-----> m=(14-10)/(-28+21)----> m=-4/7
step 2
find the equation of a line with
m=-4/7 and the point A (-21,10)
y-y1=m*(x-x1)------> y-10=(-4/7)*(x+21)---> y=(-4/7)x-12+10
y=(-4/7)x-2
step 3
find x intercept
for y=0
y=(-4/7)x-2------> 0=(-4/7)x-2-----> 4/7x=-2----> x=-14/4----> x=-3.5
the x intercept is (-3.5,0)
step 4
find the y intercept
for x=0
y=(-4/7)x-2--------> y=-2
the y intercept is (0,-2)
the answers are
the x intercept is (-3.5,0)
the y intercept is (0,-2)
see the attached figure
to find the equation of a line i need two points
let
point A-----> (-21,10)
point B-----> (-28,14)
step 1
find the slope m
m=(y2-y1)/(x2-x1)-----> m=(14-10)/(-28+21)----> m=-4/7
step 2
find the equation of a line with
m=-4/7 and the point A (-21,10)
y-y1=m*(x-x1)------> y-10=(-4/7)*(x+21)---> y=(-4/7)x-12+10
y=(-4/7)x-2
step 3
find x intercept
for y=0
y=(-4/7)x-2------> 0=(-4/7)x-2-----> 4/7x=-2----> x=-14/4----> x=-3.5
the x intercept is (-3.5,0)
step 4
find the y intercept
for x=0
y=(-4/7)x-2--------> y=-2
the y intercept is (0,-2)
the answers are
the x intercept is (-3.5,0)
the y intercept is (0,-2)
see the attached figure
Answer and explanation:
Given : The position of an object moving along an x axis is given by where x is in meters and t in seconds.
To find : The position of the object at the following values of t :
a) At t= 1 s
b) At t= 2 s
c) At t= 3 s
d) At t= 4 s
(e) What is the object's displacement between t = 0 and t = 4 s?
At t=0, x(0)=0
At t=4, x(4)=14.24
The displacement is given by,
(f) What is its average velocity from t = 2 s to t = 4 s?
At t=2, x(2)=-1.76
At t=4, x(4)=14.24
The average velocity is given by,