Question

Solving a Quadratic Equation by Completing the Square Solve x2 + 8x = 33 by completing the square. Which is the solution set of the equation? {–11, 3} {–3, 11} {–4, 4} {–7, 7}

Answer 1

Divide the coefficient of x by 2 then square the quotient.
Add the result to both sides of the equation.

$x^2 + 8x = 33$
$x^2 + 8x + (\frac{8}{2})^2 = 33 + (\frac{8}{2})^2$
$x^2 + 8x + 4^2 = 33 + 4^2$
$x^2 + 8x + 16 = 33 + 16$
$x^2 + 8x + 16 = 49$

Factor the left-hand side.

$(x + 4)^2 = 49$

Square both sides.

$x + 4 = \sqrt{49}$

Subtract both sides by 4.

$x = -4$$± \sqrt{49}$

Simplify.

$x = -4$$± 7$
So, x can either equal -4 + 7 or -4 - 7

So, the answer is {-11, 3}

NOTE: You're probably seeing a strange A in the equations. I tried to fix it, but I couldn't. Sorry about that.

Answer 2

Answer: The Answer To This Problem is {–11, 3} .Which Is Option A!!!