Average=(total number)/(number of items)
given that the final exam counts as two test, let the final exam be x. The weight of the final exams on the average is 2, thus the final exam can be written as 2x because any score Shureka gets will be doubled before the averaging.
Hence our inequality will be as follows:
(67+68+76+63+2x)/6≥71
(274+2x)/6≥71
solving the above we get:
274+2x≥71×6
274+2x≥426
2x≥426-274
2x≥152
x≥76
b] The above answer is x≥76, the mean of this is that if Shureka is aiming at getting an average of 71 or above, then she should be able to get a minimum score of 76 or above. Anything less than 76 will drop her average lower than 71.
Answer:
y=930 x 075^x
Step-by-step explanation:
y is the price after the amount of years x being plugged into the equation. 930 is what you started with. 7.5 is what is being decreased so divide that by 100 and you get 0.075 plug in the amount of years into x and you have your equation
B is the answer to the problem.
Answer:
is that 12.75 or 2.75
Step-by-step explanation:
15.8 as the square root of (13^2+9^2) is less then the square root of (10^2+14^2) you can do this by using the Pythagorean Theorem.
