Answer with explanation:
Average Height of tallest Building in San Francisco
Average Height of tallest Building in Los Angeles
→→Difference between Height of tallest Building in Los Angeles and Height of tallest Building in San Francisco
=233.9-197.8
=36.1
⇒The average height of the 10 tallest buildings in Los Angeles is 36.1 more than the average height of the tallest buildings in San Francisco.
⇒Part B
Mean absolute deviation for the 10 tallest buildings in San Francisco
|260-197.8|=62.2
|237-197.8|=39.2
|212-197.8|=14.2
|197 -197.8|= 0.8
|184 -197.8|=13.8
|183-197.8|=14.8
|183-197.8|= 14.8
|175-197.8|=22.8
|174-197.8|=23.8
|173 -197.8|=24.8
Average of these numbers
Mean absolute deviation=23.12
Answer:
12 bars of soap for $10.00, but actullay the are both the same. if u buy 5 bars of soap for $4.00 then the next time u buy 7 bars of soap, your are still using the same amount of money.
Step-by-step explanation:
A = b*h*0.5
24 = 4*0.5*h
24 = 2*h
h = 12
Height is 12 inches.
Answer:
The diner served 45 regular sodas
Step-by-step explanation:
90% of 50 is 45 so the answer is 45
Answer:
Step-by-step explanation:
Given: In parallelogram DEFG,
DH = x + 1
HF = 3y
GH = 3x - 4
and HE = 5y + 1
Solution: Since, DH,HF, GH and HE represents the diagonals of the parallelogram and we know that the diagonals of the parallelogram bisect each other, therefore
x+1=3y (1)
3x-4=5y+1 (2)
Multiply equation (1) with 3 and then subtract equation (2) from it, we get
3x+3-3x+4=9y-5y-1
7=4y-1
y=2
Substituting the value of y=2 in equation (1), we get
x+1=3(2)
x=5
Therefore, the value of x and y are 5 and 2 respectively.
