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3 years ago

Find the area of this shape

Mathematics

1 answer:

ArbitrLikvidat [17]3 years ago

8 0

So you have 2 identical big triangles with the h = 5.75 and b = 4:

A=(1/2)bh=(1/2)*4*5.75=11.5
11.5*2=23

Then you have to smaller identical triangles with the h =2 and b=(4+4-4)/2=2

A=(1/2)*2*2=2
2*2=4

Then you have a rectangle:
A=bh=4*2=8

Add all the calculated areas:
A=23+4+8=35

The area of the shape is therefore 35 cm^2

Hope that helped.

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I only need 12 and 17, first good response i will give brainliest please i’m desperate

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Answer:

$\textsf{12.} \quad y = 6x - 5$

$\textsf{17.} \quad y=-\dfrac{1}{4}x-2$

Step-by-step explanation:

<h3><u>Question 12</u></h3>

Find the slope of the line by substituting two points from the given table into the slope formula.

<u>Define the points</u>:

Let (x₁, y₁) = (2, 7)
Let (x₂, y₂) = (3, 13)

$\implies \textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{13-7}{3-2}=\dfrac{6}{1}=6$

Substitute the found slope and point (2, 7) into the point-slope formula to create an equation of the line:

$\implies y-y_1=m(x-x_1)$

$\implies y-7=6(x-2)$

$\implies y-7=6x-12$

$\implies y=6x-5$

<h3><u>Question 17</u></h3>

Given:

f(4) = 3
f(0) = -2

Therefore, two points on the line are:

(4, -3)
(0, -2)

The y-intercept is the y-value when x = 0.

Therefore, the y-intercept of the line is -2.

$\boxed{\begin{minipage}{6.3 cm}\underline{Slope-intercept form of a linear equation}\\\\$y=mx+b$\\\\where:\\ \phantom{ww}$\bullet$ $m$ is the slope. \\ \phantom{ww}$\bullet$ $b$ is the $y$-intercept.\\\end{minipage}}$