Answer:
The answer is C. Nonpolar ends of phospholipids are exposed to watee inside and outside the cell
The answer is Fist hope I helped
Given
E dominant allele for wet
e recessive allele for dry
that means
for phenotype wet, the possible genotypes are EE, or Ee, and
for phenotype dry, the only possible genotype is ee.
Therefore we also know that the child who has dry earwax has genotype ee.
Since the child inherits one allele from each parent, therefore each parent must have a recessive allele "e".
If both parents have phenotype wet earwax, they both must be heterozygous for wet/dry earwax, namely Ee.
The correct answer is none of the above.
Bacterial cells can transfer genetic material through a process called bacterial conjugation. This process involves the direct physical contact of the bacterial cells and a horizontal gene transfer. The genes which are transferred are most of the times beneficial for the recipient, such as genes for antibiotic resistance.
In this example, bacterial cells cannot have physical contact, since they are separated by a glass filter. Therefore, the bacterial conjugation cannot happen. Given that no gene transfer can be achieved, the AY strain remains bio- trp- and is unable to grow on any medium that lacks bio or/and trp.
Answer:
They will collapse and shut off the stomatal pore
Explanation:
The guard cells are regulated by the presence of water. When water is present, they become turgid and open up the stomatal pore and when water is inadequate, they become flaccid, collapse and close up the stomatal pore as a result.
<em>If the leaf is left under the microscope for too long, there will be loss of water by evapotranspiration and the guard cell will become flaccid and collapse as a result and the stomatal pore will become closed.</em>
