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slamgirl [31]
4 years ago
13

Which values are equivalent to the fraction below ? Check all that apply. (3 ^ 6)/(3 ^ 8) A. 3 ^ - 3 (1/3) ^ 3 5/8 D. 1/27 O 3 ^

13 O 3 ^ 3 SUBMI
Mathematics
2 answers:
Doss [256]4 years ago
5 0

Answer:

1/9

Step-by-step explanation:

liubo4ka [24]4 years ago
3 0

Answer:

1/9

Step-by-step explanation:

your welcome

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the correct answer for this problem: x= -1/3y + 2

Let’s solve for x
3x + y= 6

Add -y to both sides
3x + y + -y = 6+ -y
3x = -y + 6

Divide both sides by 3
3x/3 = -y + 6/ 3

And so your answer is at the top hope this helps.
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Suppose on a certain test, fifty students earn a perfect score and fifty students earn a zero. Determine the mean grade and stan
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B=26-8
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Find the difference in the volume and total area of a cylinder with both a radius and height of 1.
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Let c be the path c(t) = (2t, t2, log(t)), defined for t > 0. find the arc length of c between the points (2, 1, 0) and (12,
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The path starts at t=1 and ends at t=6, so we have an arc length of


\displaystyle\int_{\mathcal C}\mathrm dS=\int_{t=1}^{t=6}\|\mathbf c'(t)\|\,\mathrm dt
=\displaystyle\int_1^6\sqrt{2^2+(2t)^2+\left(\frac1t\right)^2}\,\mathrm dt
=\displaystyle\int_1^6\sqrt{4t^2+4+\frac1{t^2}}\,\mathrm dt
=\displaystyle\int_1^6\frac1t\sqrt{4t^4+4t^2+1}\,\mathrm dt
=\displaystyle\int_1^6\frac1t\sqrt{(2t^2+1)^2}\,\mathrm dt
=\displaystyle\int_1^6\frac{2t^2+1}t\,\mathrm dt
=\displaystyle\int_1^6\left(2t+\frac1t\right)\,\mathrm dt
=t^2+\log t\bigg|_{t=1}^{t=6}
=(6^2+\log6)-(1^2+\log1)=35+\log6
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4 years ago
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