Question

The Mayors of two small towns that adjoin a large community have engaged in an argument on which of their cities is safer, with respect to its crime rate. City A has a residential population of 123,000 people and reported 185 violent crimes. City B has a residential population of 84,000 people and reported 135 violent crimes. Answer the following questions. 1. What is the reported crime rate per 100,000 residents in both cities? 2. Based on your responses to the previous question, which city has the lowest crime rate?

Answer 1

Answer:

1. City A: 150 violent crimes per 100,000 residents.

   City B: 161 violent crimes per 100,000 residents.

2. City A

Step-by-step explanation:

City A:

Population = 123,000

Violent crimes = 185

Violent crimes per 100,000 people:

$V_{100k} = \frac{185*100,000}{123,000} \\V_{100k} = 150$

City B:

Population = 84,000

Violent crimes = 135

Violent crimes per 100,000 people:

$V_{100k} = \frac{135*100,000}{84,000} \\V_{100k} = 161$

1. City A: 150 violent crimes per 100,000 residents.

   City B: 161 violent crimes per 100,000 residents.

2. Even though it has a bigger number of crimes, City A has the lowest crime rate since its population is larger.