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3 years ago

5

Complete this table. Function : f(x)=2x-1 1 _ 2 _ 3 _ 4 _

1 answer:

liq [111]3 years ago

8 0

Answer:

Look at the photo below.

:)

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How many different arrangements are there of the letters a, b, c, d, e, f for which e is not last in line?

Olegator [25]

Hmm, there are 5 letters

if you cannot repeat the letters
hmm, let's find how many for 4 letters
there are 4! or 4*3*2*1=24
that's how many ways there are to arrange a,b,c, d
now we can multiply it by 4 because there are 4 choices for the last place (e is not included0
24*4=56
answer is 56 different arrangements

6 0

3 years ago

A rectangle's length is three times its width. Let w denote the rectangle's width. What polynomial represents the rectangle's ar

Nataliya [291]

Width = W
Length = 3 times w = 3W

Area = length x width = 3W * W = 3W^2

8 0

2 years ago

In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= 2 cm.

konstantin123 [22]

Consider right triangle ΔABC with legs AC and BC and hypotenuse AB. Draw the altitude CD.

1. Theorem: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.

According to this theorem,

$BC^2=BD\cdot AB.$

Let BC=x cm, then AD=BC=x cm and BD=AB-AD=3-x cm. Then

$x^2=(3-x)\cdot 3,\\ \\x^2=9-3x,\\ \\x^2+3x-9=0,\\ \\D=3^2-4\cdot (-9)=9+36=45,\\ \\\sqrt{D}=\sqrt{45}=3\sqrt{5},\\ \\x_1=\dfrac{-3-3\sqrt{5} }{2}0.$

Take positive value x. You get

$AD=BC=\dfrac{-3+3\sqrt{5} }{2}\ cm.$

2. According to the previous theorem,

$AC^2=AD\cdot AB.$

Then

$AC^2=\dfrac{-3+3\sqrt{5} }{2}\cdot 3=\dfrac{-9+9\sqrt{5} }{2},\\ \\AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.$

Answer: $AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.$

This solution doesn't need CD=2 cm. Note that if AB=3cm and CD=2cm, then

$CD^2=AD\cdot DB,\\ \\2^2=AD\cdot (3-AD),\\ \\AD^2-3AD+4=0,\\ \\D$

This means that you cannot find solutions of this equation. Then CD≠2 cm.

8 0

3 years ago

Read 2 more answers

PLEASE HELP!!!!

Lisa [10]

Answer:

x = - 3 with multiplicity 2

Step-by-step explanation:

f(x) = (x - 3)(x + 3)(x + 3) = (x - 3)(x + 3)²

Equating each factor to zero and solving for x

x - 3 = 0 ⇒ x = 3 with multiplicity 1

x + 3 = 0 ⇒ x = - 3

x + 3 = 0 ⇒ x = -3

Thus x = - 3 has multiplicity of 2

The fact that the factor is squared gives the multiplicity

(x + 3)³ has root - 3 of multiplicity 3

8 0

2 years ago

Helpppppppppppp meeeeeee

MArishka [77]

Answer:

7

Step-by-step explanation:

4 0

2 years ago