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Sedaia [141]
3 years ago
5

Find the value of the expression 2x²-5x+6

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
7 0
33x I think sorry if I am wrong
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You start a savings account and on the first week you deposit $2. Every
vlada-n [284]

Answer:

558 weeks

Step-by-step explanation:

let x = number of weeks

this equation can be derived from the question

2 + 1x = 560

collect like terms

x = 560 - 2

x = 558

5 0
3 years ago
Find the general solution of the differential equation y′′−14y′+51 y=0. Considered as an independent variable. Use C1, C2, C3, .
meriva

Answer:

Step-by-step explanation:

Jjzjzjdnxnxnxnxnnxnxnxjjxjskakenejjrjrjfjfnfnfjrjrjfjjfjrnrnfnfmfmfmfnfjfjf

4 0
3 years ago
8.
Svetradugi [14.3K]

Answer:

B

Step-by-step explanation:

Using the rule of exponents

a^{-m} = \frac{1}{a^{m} }

Given

y = 12 × 3^{x} ← substitute x = - 2 into the expression

y = 12 × 3^{-2} = 12 × \frac{1}{3^{2} } = 12 × \frac{1}{9} = \frac{12}{9} = \frac{4}{3} → B

7 0
3 years ago
Read 2 more answers
On New​ Year's Eve, the probability of a person driving while intoxicated or having an accident is 0.37. If the probability of d
max2010maxim [7]

Answer:

The probability of a person having a driving accident while intoxicated is 0.07

Step-by-step explanation:

Hi, well, let´s put this on a formula, I think it is the best way to explain it.

P(A+I)=P(A)+P(I)-P(AorI)

Where:

P(A+I) = Probability of having a driving accident while intoxicated.

P(A) = Probability of a person of having an accident.

P(I) = Probablity person being intoxicated.

P(A or I) = Probability of a person for being intoxicated or having an accident.

Therefore, things should look like this:

P(A+I)=0.12+0.32-0.37=0.07

So, the  probability of a person having a driving accident while intoxicated is 0.07.

Best of luck.

5 0
3 years ago
1+1x5
Lesechka [4]

Answer:

10 eheyyahwhwhahwhwhwhwhwhhe

4 0
3 years ago
Read 2 more answers
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