<u>f(x) = x + 3</u>
f(2) = 2 + 3
f(2) = 5
f(4) = 4 + 5
f(4) = 9
f(6) = 6 + 5
f(6) = 11
{(2, 5), (4, 9), (6, 11)}
Answer:
x^2-6x+5
Step-by-step explanation:
To have roots at x=5 and x=1 you need to write is as follows
(x-5)(x-1)
you then need to multiply these two and get
x^2-6x+5
<span> here
7 7/8
= [ (8*7) + 7 ] / 8
= (56 + 7) / 8
=63 / 8
similarly,
3 1/4
=[ (4*3) + 1] / 4
= (12 + 1) / 4
= 13/4
----------------------------
now put the values
7 7/8 - 3 1/4
= 63/8 - 13/4
here, take LCM of 8 & 4 which is 8.
now,
[ (1*63) - (2 * 13) ] / 8
= (63 - 26) / 8
= 37/8
= 4 5/8........................[ here, divide 37 by 8 which gives reminder as 5 and divisible value as 4 ]</span>
Answer:
Total possible ways to select 6 teachers from 34 teacher are
.
Step-by-step explanation:
It is given that total number of teachers at a school is 34.
The school director must randomly select 6 teachers to part in a training session.

Where, n is total possible outcomes and r is number of selected outcomes.
Total teachers = 34
Selected teachers =6
Total number of possible ways to select 6 teachers from 34 teacher is



Therefore total possible ways to select 6 teachers from 34 teacher are
.