A $129 golf club is on sale

If the endpoints of the diameter of a circle are (6, 3) and (2, 1), what is the standard form equation of the circle?

Anastasy [175]

If the endpoints of a diameter are (6,3) and (2,1) the midpoint is the center of the circle so:

(x,y)=((6+2)/2, (3+1)/2)=(4,2)

Now we need to find the radius....the diameter is:

d^2=(6-2)^2+(3-1)^2

d^2=16+4

d^2=20 since d=2r, r=d/2, and r^2=d^2/4 so

r^2=5

The standard form of the circle is (x-h)^2+(y-k)^2=r^2 and we know:

(h,k)=(4,2) from earlier so:

(x-4)^2+(y-2)^2=5

8 0

3 years ago

Y = -x + 3<br> What is the slope for this?

ICE Princess25 [194]

The slope for this equation is x=3

5 0

3 years ago

Checking my work. which one?

Genrish500 [490]

Answer:

Dividing exponents you subtract.

3^8/3^5 = 3^3

3^3

Multiplying exponents when an exponent is raised to another.

(3^3)^3 = <u>3^9</u>

<h2>Final Answer is $3^{9}$ </h2><h2 />

Apparently this makes no sense according to comments, if you want a more indepth look into exponents search "The properties of exponents".

6 0

2 years ago

Read 2 more answers

What does h equal in the equation S=2πr2+2πrh?

Troyanec [42]

A

Step-by-step explanation:First, subtract

2

π

r

2

from each side of the equation to isolate the

h

term:

S

−

2

π

r

2

=

2

π

r

h

+

2

π

r

2

−

2

π

r

2

S

−

2

π

r

2

=

2

π

r

h

+

0

S

−

2

π

r

2

=

2

π

r

h

Now, divide each side of the equation by

2

π

r

to solve for

h

:

S

−

2

π

r

2

π

r

=

2

π

r

h

2

π

r

S

−

2

π

r

2

π

r

=

2

π

r

h

2

π

r

S

−

2

π

r

2

π

r

=

h

=

S

−

2

π

r

2

π

r

Or

h

=

S

2

π

r

−

2

π

r

2

π

r

h

=

S

2

π

r

−

2

π

r

2

π

r

h

=

S

2

π

r

−

r

2

r

h

=

S

2

π

r

−

r

4 0

3 years ago

Mr. Schordine wants to fill up enough helium balloons to allow him to fly through the skies. He weighs 84 kilograms. He knows th

Cerrena [4.2K]

Answer:

There is needed around 311 balloons to fulfill Mr. Schordine’s dream of flight.

Step-by-step explanation:

First, we need to calculate the volume of each balloon by considering the balloons as a sphere:

$V = \frac{4}{3}\pi r^{3}$

Where:

r: is the radius = 0.4 meters

$V = \frac{4}{3}\pi r^{3} = \frac{4}{3}\pi (0.4 m)^{3} = 0.27 m^{3}$

Knowing that 1 m³ of helium is able to lift about 1 kg, that Mr. Schordine weights 84 kg, and that each ballon has 0.27 m³ of helium, the number of balloons needed are:

$N = \frac{1 m^{3}}{1 kg}*84 kg*\frac{1 balloon}{0.27 m^{3}} = 311.1 \: balloon$

Therefore, there is needed around 311 balloons to fulfill Mr. Schordine’s dream of flight.

I hope it helps you!

6 0

3 years ago