Question

a fruit stand has to decide what to charge for their produce. They need $10 for 4 apples and 4 oranges. They also need $12 for 6 apples and 6 oranges. We put information into a system of linear equations.

Answer 1

Answer:

X = apple

y = orange

4x + 4y = 10

6x + 6y = 12

Step-by-step explanation:

Answer 2

Answer:

4a+4r = 10

6a + 6r = 12

No solutions

Step-by-step explanation:

a = cost of the apple

r = cost of the orange

4a+4r = 10

6a + 6r = 12

Divide the first  equation by 2 and the second equation by 6

2a+2r = 5

a +r = 2

Multiply the second equation by -2 so we can eliminate a

-2a -2r = -4

Add the first equation

2a+2r = 5

-2a -2r = -4

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0 = 1

This system is inconsistent and has no solutions