a fruit stand has to decide what to charge for their produce. They need $10 for 4 apples and 4 oranges. They also need $12 for 6
apples and 6 oranges. We put information into a system of linear equations.
2 answers:
Answer:
X = apple
y = orange
4x + 4y = 10
6x + 6y = 12
Step-by-step explanation:
Answer:
4a+4r = 10
6a + 6r = 12
No solutions
Step-by-step explanation:
a = cost of the apple
r = cost of the orange
4a+4r = 10
6a + 6r = 12
Divide the first equation by 2 and the second equation by 6
2a+2r = 5
a +r = 2
Multiply the second equation by -2 so we can eliminate a
-2a -2r = -4
Add the first equation
2a+2r = 5
-2a -2r = -4
---------------------
0 = 1
This system is inconsistent and has no solutions
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Hope this helped :)
Sorry I really need point but I wish you good luck!
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