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3 years ago

Fracciones equivalentes a 2/8

Mathematics

1 answer:

jeyben [28]3 years ago

5 0

$\dfrac{2}{8} = \dfrac{2 \div 2}{8 \div 2} = \dfrac{1}{4}$

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KiRa [710]

Answer:

Average range(R-bar) = Sum of the sample range for each sample/number of samples = (9+8+1+8+7) /5 = 33/5 = 6.6

Sample size = 8

For a sample size of 8 the factors for control limit for range (D3) = 0.136 (obtained from table of constraints for x-bar and R chart

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Step-by-step explanation:

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3 years ago

Find the vectors T, N, and B at the given point. r(t) = < t^2, 2/3t^3, t >, (1, 2/3 ,1)

maxonik [38]

Answer with Step-by-step explanation:

We are given that

$r(t)=< t^2,\frac{2}{3}t^3,t >$

We have to find T,N and B at the given point t > (1, $2/3$ ,1)

$r'(t)=$

$\mid r'(t) \mid=\sqrt{(2t)^2+(2t^2)^2+1}=\sqrt{(2t^2+1)^2}=2t^2+1$

$T(t)=\frac{r'(t)}{\mid r'(t)\mid}=\frac{}{2t^2+1}$

Now, substitute t=1

$T(1)=\frac{}{2+1}=\frac{1}{3}$

$T'(t)=\frac{-4t}{(2t^2+1)^2} +\frac{1}{2t^2+1}$

$T'(1)=-\frac{4}{9}+\frac{1}{3}$

$T'(1)=\frac{1}{9}=$

$\mid T'(1)\mid=\sqrt{(\frac{-2}{9})^2+(\frac{4}{9})^2+(\frac{-4}{9})^2}=\sqrt{\frac{36}{81}}=\frac{2}{3}$

$N(1)=\frac{T'(1)}{\mid T'(1)\mid}$

$N(1)=\frac{}{\frac{2}{3}}=$

$N(1)=$

$B(1)=T(1)\times N(1)$

$B(1)=\begin{vmatrix}i&j&k\\\frac{2}{3}&\frac{2}{3}&\frac{1}{3}\\\frac{-1}{3}&\frac{2}{3}&\frac{-2}{3}\end{vmatrix}$

$B(1)=i(\frac{-4}{9}-\frac{2}{9})-j(\frac{-4}{9}+\frac{1}{3})+k(\frac{4}{9}+\frac{2}{9})$

$B(1)=-\frac{2}{3}i+\frac{1}{3}j+\frac{2}{3}k$

$B(1)=\frac{1}{3}$

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3 years ago

Is 70x8=490 pls answer

Anna71 [15]

Answer:

Step-by-step explanation:

70 * 8 = 560, not 490

Instead, 70 * 7 = 490

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3 years ago

Read 2 more answers

What is the unit rate for 6 pack soda for $7.96

Allisa [31]

7.96 / 6 = 1.33 <== unit rate

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3 years ago

What is the least number n with the property that, in every group of n people, there are at least three people who are all frien

8_murik_8 [283]

Answer:

hello your question is incomplete attached below is a the complete question

answer : n = 5

Step-by-step explanation:

lets consider N to be 5

To prove that the least number 'n' = 5

we will represent this information in a graph as vertex

Black edge = Friends

Blue edge = not Friends

From the attached diagram any vertex contains 0,1,2,3,4 black lines and 4,3,2,1,0 blue lines

attached below is an explanation related to the choice of n = 5

considering n = 5 is satisfied by the explanation given

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2 years ago