An are whose measure is exactly 180°

Mathematics

1 answer:

Elenna [48]3 years ago

5 0

Answer:

Mmeasure is exactly 180°

semi-circle because the measure of a whole circle is 360°.

Arc :

The arc of a circle consists of two points on the circle and all of the points on the circle that lie between those two points. It's like a segment that was wrapped partway around a circle. An arc is measured not by its length (although it can be, of course) but most often by the measure of the angle whose vertex is the center of the circle and whose rays intercept the endpoints of the arc. Hence an arc can be anywhere from 0 to 360 degrees.

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How many ways are there to put 6 balls in 3 boxes if three balls are indistinguishably white, three are indistinguishably black,

erik [133]

Let the boxes be Box 1, Box 2, Box 3.

consider the 3 white balls. They can be all of them in one box:

(3, 0, 0) (3 in Box 1, 0 in box 2 and 0 in box 0)
(0, 3, 0)
(0, 0, 3)

We can have 2 in one box, and 1 in one of the remaining boxes:

(2, 0, 1)
(2, 1, 0)
(0, 2, 1)
(1, 2, 0)
(0, 1, 2)
(1, 0, 2)

and there is only one way: (1, 1, 1) to place one white ball in each box

In total there are: 3+6+1=10 ways to place the white balls. Similarly there are 10 ways to place the black ones.

Since every placement of the white balls can be combined with any placement of the black balls, there are 10*10=100 ways to place the 3white balls and the 3 black bals in the boxes.

Answer: 100

4 0

3 years ago

Read 2 more answers

Solve for p: 3/8 +p/8= 3 1/8

Ivenika [448]

Solve for p:
p/8 + 3/8 = 25/8
p/8 + 3/8 = (p + 3)/8:
(p + 3)/8 = 25/8

Multiply both sides of (p + 3)/8 = 25/8 by 8:
(8 (p + 3))/8 = (8×25)/8
(8×25)/8 = (8×25)/8:
(8 (p + 3))/8 = (8×25)/8
(8 (p + 3))/8 = 8/8×(p + 3) = p + 3:p + 3 = (8×25)/8
(8×25)/8 = 8/8×25 = 25:
p + 3 = 25

Subtract 3 from both sides:
p + (3 - 3) = 25 - 3
3 - 3 = 0:
p = 25 - 3
25 - 3 = 22:
Answer: p = 22

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3 years ago

The area of the regular hexagon is 169.74 ft2 what is the perimeter, rounded to the nearest tenth

Bess [88]

Answer:

Perimeter of given regular hexagon is 48.5 ft.

Step-by-step explanation:

Let ABCDEF be the regular hexagon as shown in the attached figure.

O be the intersection point of the diagonals EB, FC and AD.

As per the property of regular hexagon, all the 6 triangles formed are equilateral triangles.

In other words,

$\triangle EOD, \triangle DOC, \triangle BOC, \triangle AOB, \triangle AOF , \triangle FOE$ are equilateral $\triangle s$ .