The maximum area of the school soccer field is given by the maximum length times the maximum width.
Thus maximum area = 120 x 80 = 9,600 square yards.
The minimum area of the school soccer field is given by the minimum length times the minimum width.
Thus maximum area = 100 x 55 = 5,500 square yards.
Therefore, the difference between the maximum area and the minimum area is 9,600 - 5,500 = 4,100 square yards.
Answer:
Answer:
The range is 15
Explanation:
The box and whisker plot is from 5 to 20
The range is:
20 - 5 =15
So the second question asks about the perimeter of a rectangular pool and the answer for that is W=87m.
I don’t know about the first question sorry but I’ll try figuring it out.
She spent 1/3 of 3/4. Or about 0.25, or about 1/4 in fractions.
Answer:
x = 2 and y = 5
Step-by-step explanation:
Given the simultaneous linear equations
y = 2x + 1 and x + y = 7
We are to find the value of x and y;
Substitute 1 into 2
From 2;
x+y = 7
x+2x+1 = 7
3x+1 = 7
3x = 7-1
3x = 6
x = 6/3
x = 2
Recall that y = 2x+1
y = 2(2) + 1
y = 4+1
y = 5
Hence the solution from the graph will be the point where the line cuts the x axis and this will be at x = 2 and y = 5
