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4 years ago

Calculate the density of the following objects:

Chemistry

1 answer:

KonstantinChe [14]4 years ago

7 0

Answer:

Density =M/V

1500/7600

5.0666666667=Ans...

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What does a particular point on a line of a phase diagram represent ?

Artemon [7]

Answer:

It's D.

Explanation:

The lines on the phase diagram represent combinations of pressures and temperatures at which two phases coexist in equilibrium

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3 years ago

Read 2 more answers

Determine the concentration of sulfuric acid that needed 47 mL of 0.39M potassium hydroxide solution to neutralize a 25 mL sampl

Ugo [173]

0.73 M is the concentration of sulfuric acid that needed 47 mL of 0.39M potassium hydroxide solution to neutralize a 25 mL sample of the sulfuric acid solution.

Explanation:

Data given:

Volume of the base = 47 ml

molarity of the base= 0.39 M

volume of the acid = 25 ml

molarity of the acid =?

For titration reaction between acid and base, the volume or molarity of any of the base or acid can be determined. The formula used:

Macid X Vacid = Vbase x Mbase

Macid = $\frac{Vbase X M base}{V acid}$

putting the values given in the rearranged equation above:

Macid = $\frac{0.39 x47}{25}$

= 0.73 M

The concentration of the sulphuric acid needed is 0.73 M.

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4 years ago

Which determines the state of matter for any material?

Paul [167]

Answer: the answer is A and C

Explanation: because they are really kind of both the same

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4 years ago

In a laboratory, 1.55mg of an organic compound containing carbon, hydrogen, and oxygen is burned for analysis. This combustion r

Serjik [45]

Answer:

CH₃O

Step-by-step explanation:

1. Calculate the mass of each element

Mass of C = 1.45 mg CO₂ × (12.01 mg C/44.01 mg CO₂) = 0.3957 mg C

Mass of H = 0.89 mg H₂O × (2.016 mg H/18.02 mg H₂O) = 0.0996 mg H

Mass of O = Mass of compound - Mass of C - Mass of H = (1.55 – 0.3957 – 0.0996) mg = 1.055 mg

2. Calculate the moles of each element

Moles of C = 0.3957 mg C × 1mmol C/12.01 mg C = 0.03295 mol C

Moles of H = 0.0996 mg H × 1 mmol H/1.008 mg H = 0.0988 mol H

Moles of O = 1.055 mg O × 1 mmol O/ 16.00 mg O = 0.06592 mol O

3. Calculate the molar ratios

Divide all moles by the smallest number of moles.

C: 0.032 95/0.032 95 = 1

H: 0.0988/0.032 95 = 2.998

O: 0.065 92/0.032 95 = 2.001

4. Round the ratios to the nearest integer

C:H:O = 1:3:2

5. Write the empirical formula

The empirical formula is CH₃O.

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4 years ago

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Explanation:

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3 years ago