Determine the concentration of sulfuric acid that needed 47 mL of 0.39M potassium hydroxide solution to neutralize a 25 mL sampl
1 answer:
0.73 M is the concentration of sulfuric acid that needed 47 mL of 0.39M potassium hydroxide solution to neutralize a 25 mL sample of the sulfuric acid solution.
Explanation:
Data given:
Volume of the base = 47 ml
molarity of the base= 0.39 M
volume of the acid = 25 ml
molarity of the acid =?
For titration reaction between acid and base, the volume or molarity of any of the base or acid can be determined. The formula used:
Macid X Vacid = Vbase x Mbase
Macid =
putting the values given in the rearranged equation above:
Macid =
= 0.73 M
The concentration of the sulphuric acid needed is 0.73 M.
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2. 90 mg
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1 mole of ozone is removed by 2 moles of sodium iodide.
Thus moles of ozone is removed by =
moles of sodium iodide.
Thus moles of sodium iodide are needed to remove
moles of
2.
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1 mole of ozone is removed by 2 moles of sodium iodide.
Thus 0.0003 moles of ozone is removed by = moles of sodium iodide.
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Answer:
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Explanation:
The name of the molecule with a carbon atoms arranged in a straight chain with a triple bond between the second and third carbons is 2 - Butyne.
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Hence, the given molecules described is 2 - Butyne.
