Determine the concentration of sulfuric acid that needed 47 mL of 0.39M potassium hydroxide solution to neutralize a 25 mL sampl
1 answer:
0.73 M is the concentration of sulfuric acid that needed 47 mL of 0.39M potassium hydroxide solution to neutralize a 25 mL sample of the sulfuric acid solution.
Explanation:
Data given:
Volume of the base = 47 ml
molarity of the base= 0.39 M
volume of the acid = 25 ml
molarity of the acid =?
For titration reaction between acid and base, the volume or molarity of any of the base or acid can be determined. The formula used:
Macid X Vacid = Vbase x Mbase
Macid =
putting the values given in the rearranged equation above:
Macid =
= 0.73 M
The concentration of the sulphuric acid needed is 0.73 M.
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M = molar mass of the gas in kg/mol
T = temperature in Kelvin
According to the ideal gas law,
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RT =
Substitute in the rms velocity formula,
P = 92 kPa, V = 10 L, n = 2 moles and M = 32 x 10⁻³ kg/mol
=293.68 m/s
Thus, the effective speed (rms) of O₂ gas is 293.68 m/s.
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