Question

Determine the concentration of sulfuric acid that needed 47 mL of 0.39M potassium hydroxide solution to neutralize a 25 mL sample of the sulfuric acid solution?

Answer 1

0.73 M is the concentration of sulfuric acid that needed 47 mL of 0.39M potassium hydroxide solution to neutralize a 25 mL sample of the sulfuric acid solution.

Explanation:

Data given:

Volume of the base = 47 ml

molarity of the base= 0.39 M

volume of the acid = 25 ml

molarity of the acid =?

For titration reaction between acid and base, the volume or molarity of any of the base or acid can be determined.  The formula used:

Macid X Vacid = Vbase x Mbase

Macid = $\frac{Vbase X M base}{V acid}$

putting the values given in the rearranged equation above:

Macid = $\frac{0.39 x47}{25}$

           = 0.73 M

The concentration of the sulphuric acid needed is 0.73 M.