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Talja [164]
3 years ago
11

A statistics tutor wants to assess whether her remedial tutoring has been effective for her five students. She decides to conduc

t a related samples t-test and records the following grades for students prior to and after receiving her tutoring.
Tutoring
Before After
2.4 3.1
2.5 2.8
3.0 3.6
2.9 3.2
2.7 3.5
Test whether or not her tutoring is effective at a 0.05 level of significance. State the value of the test statistic. (Round your answer to three decimal places.)
t =
Compute effect size using estimated Cohen's d. (Round your answer to two decimal places.)
d =

Mathematics
1 answer:
Snezhnost [94]3 years ago
8 0

Answer:

The test statistic value is, <em>t</em> = -5.245.

The effect size using estimated Cohen's d is 2.35.

Step-by-step explanation:

A paired <em>t</em>-test would be used to determine whether the remedial tutoring has been effective for the statistics tutor's five students.

The hypothesis can be defined as follows:

<em>H</em>₀: The remedial tutoring has not been effective, i.e. <em>d</em> = 0.

<em>Hₐ</em>: The remedial tutoring has been effective, i.e. <em>d</em> > 0.

Use Excel to perform the Paired <em>t</em> test.

Go to Data → Data Analysis → t-test: Paired Two Sample Means

A dialog box will open.

Select the values of the variables accordingly.

The Excel output is attached below.

The test statistic value is, <em>t</em> = -5.245.

Compute the effect size using estimated Cohen's d as follows:

\text{Cohen's d}=\frac{Mean_{d}}{SD_{d}}

                =\frac{0.54}{0.23022}\\\\=2.34558\\\\\approx 2.35

Thus, the effect size using estimated Cohen's d is 2.35.

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b)

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10 - 37            9.5-37.5                   23.5            7     0.096     7      

38 - 65           37.5-65.5                 51.5           25    0.342     32    

66 - 93           65.5-93.5                 79.5          26    0.356     58    

94 -  121        93.5-121.5                   107.5         9     0.123       67    

122 - 149      121.5-149.5                  135.5         5      0.068     72  

150 - 177       149.5-177.5                  163.5        0         0.0      72    

178 - 205       177.5-20.5                  191.5         1       0.014      73  

Total                                                                  73          1.0    

c)

The histogram is in attached file.

Step-by-step explanation:

a)

The width of class interval=range/desired number of classes

The width of class interval=(maximum-minimum)/7

The width of class interval=(200-10)/7

The width of class interval=190/7

The width of class interval=27.14=28 (rounded to next whole number)

Part(b) and part (c) is explained in attached word document.

Download docx
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