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Ede4ka [16]
3 years ago
10

A rectangle has a height of 2x^4 with a width of x^2+8x+15. Express the area of the rectangle.

Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
8 0

Hi there!

We know that the formula for the area of a rectangle is height * width. Thus, we can multiply these two expressions together:

2x^4\cdot (x^2+8x+15)\\

Now, we know through the distributive property that we can distribute the 2x^4\\ to everything in the parenthesis. Once this is done, we get:

2x^4 \cdot x^2+2x^4\cdot8x+2x^4\cdot15

Now, we know through the power rule that when two exponents are multiplied together with the same base, the exponent can be added together (x^a \cdot x^b = x^{a+b}). This then would make our equation:

2x^{4+2}+16x^{4+1}+30x^4\\

Giving us for our final answer:

2x^{6}+16x^{5}+30x^4\\

Hope this helps!

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kodGreya [7K]

Answer: 2.11 s

Step-by-step explanation:

Given

Equation of rockets height is given by

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Height will be zero once the rocket lands on the ground

So, we can write

\Rightarrow h(t)=0\ \text{or}\ -8t^2+16t+2=0\\\Rightarrow 8t^2-16t-2=0\\\\\Rightarrow t=\dfrac{16\pm \sqrt{(-16)^2-4(8)(-2)}}{2\times 8}\\\\\Rightarrow t=\dfrac{16\pm \sqrt{320}}{16}\\\\\text{Neglecting negative value of t}\\\\\Rightarrow t=\dfrac{16+17.888}{16}=2.11\ s

7 0
2 years ago
g If there are 52 cards in a deck with four suits (hearts, clubs, diamonds, and spades), how many ways can you select 5 diamonds
dezoksy [38]

Answer:

The number of ways to select 5 diamonds and 3 clubs is 368,082.

Step-by-step explanation:

In a standard deck of 52 cards there are 4 suits each consisting of 13 cards.

Compute the probability of selecting 5 diamonds and 3 clubs as follows:

The number of ways of selecting 0 cards from 13 hearts is:

{13\choose 0}=\frac{13!}{0!\times(13-0)!} =\frac{13!}{13!}=1

The number of ways of selecting 3 cards from 13 clubs is:

{13\choose 3}=\frac{13!}{3!\times(13-3)!} =\frac{13!}{13!\times10!}=286

The number of ways of selecting 5 cards from 13 diamonds is:

{13\choose 5}=\frac{13!}{5!\times(13-5)!} =\frac{13!}{13!\times8!}=1287

The number of ways of selecting 0 cards from 13 spades is:

{13\choose 0}=\frac{13!}{0!\times(13-0)!} =\frac{13!}{13!}=1

Compute the number of ways to select 5 diamonds and 3 clubs as:

{13\choose0}\times{13\choose3}\times{13\choose5}\times{13\choose0} = 1\times286\times1287\times1=368082

Thus, the number of ways to select 5 diamonds and 3 clubs is 368,082.

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