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Furkat [3]
3 years ago
15

How does the suffix help you understand the meaning of announcement

Mathematics
1 answer:
sergeinik [125]3 years ago
6 0
The suffix 'ment' belongs to nouns that denote an action. the word 'announce' means to declare or make something known. So the word 'announcement' is the action of declaring.
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HELP PLEASE ASAP!!!
natulia [17]

Answer:

Step-by-step explanation:

f(x)=3x-2

f(2)=3(2)-2

f(2)=6-2

f(2)=4

When you solve f(x) for x=2, you get f(2)=4. This means that g(f(2)) is equal to g(4). Now, you can solve g(x) for x=4.

g(4)=4^2-5

g(4)=16-5

g(4)=11

g(f(2))=11

So the answer is A, 11.

7 0
3 years ago
What are the necessary criteria for a line to be perpendicular to the given line and have the same y-intercept?
svetlana [45]
Y=-(3/5)x-7is the anwser because this is the form y=mx+b where m=5/3 any line perpendicular to this given line will have the slope of -1/m so, in this case slope of perpendicular is: -1/(5/3) = -3/5 we know the y-intercept is -7, point (0, -7) so wave: <span>y = -(3/5)x - 7</span>
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3 years ago
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In May, there were 157 people living in Kristin's neighborhood. By August, the population had increased 21%. How many people wer
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Barbara Bailey joined a bowling league. She paid a $18.00 entry fee plus $7.50 a week for 16 weeks. She purchased a bowling ball
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3 years ago
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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Consider the functions given below. SEE F
Wewaii [24]

Answer:

1. P(x) ÷ Q(x)---> \frac{-3x + 2}{3(3x - 1)}

2. P(x) + Q(x)---> \frac{2(6x - 1)}{(3x - 1)(-3x + 2)}

3.  P(x) - Q(x)---> \frac{-2(12x - 5)}{(3x - 1)(-3x + 2)}

4. P(x)*Q(x) --> \frac{12}{(3x - 1)(-3x + 2)}

Step-by-step explanation:

Given that:

1. P(x) = \frac{2}{3x - 1}

Q(x) = \frac{6}{-3x + 2}

Thus,

P(x) ÷ Q(x) = \frac{2}{3x - 1} ÷ \frac{6}{-3x + 2}

Flip the 2nd function, Q(x), upside down to change the process to multiplication.

\frac{2}{3x - 1}*\frac{-3x + 2}{6}

\frac{2(-3x + 2)}{6(3x - 1)}

= \frac{-3x + 2}{3(3x - 1)}

2. P(x) + Q(x) = \frac{2}{3x - 1} + \frac{6}{-3x + 2}

Make both expressions as a single fraction by finding, the common denominator, divide the common denominator by each denominator, and then multiply by the numerator. You'd have the following below:

\frac{2(-3x + 2) + 6(3x - 1)}{(3x - 1)(-3x + 2)}

\frac{-6x + 4 + 18x - 6}{(3x - 1)(-3x + 2)}

\frac{-6x + 18x + 4 - 6}{(3x - 1)(-3x + 2)}

\frac{12x - 2}{(3x - 1)(-3x + 2)}

= \frac{2(6x - 1}{(3x - 1)(-3x + 2)}

3. P(x) - Q(x) = \frac{2}{3x - 1} - \frac{6}{-3x + 2}

\frac{2(-3x + 2) - 6(3x - 1)}{(3x - 1)(-3x + 2)}

\frac{-6x + 4 - 18x + 6}{(3x - 1)(-3x + 2)}

\frac{-6x - 18x + 4 + 6}{(3x - 1)(-3x + 2)}

\frac{-24x + 10}{(3x - 1)(-3x + 2)}

= \frac{-2(12x - 5}{(3x - 1)(-3x + 2)}

4. P(x)*Q(x) = \frac{2}{3x - 1}* \frac{6}{-3x + 2}

P(x)*Q(x) = \frac{2*6}{(3x - 1)(-3x + 2)}

P(x)*Q(x) = \frac{12}{(3x - 1)(-3x + 2)}

4 0
3 years ago
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