The length of a rectangle is twice it’s width of the area of the rectangle is 50 in^2 , find its perimeter.

1 answer:

8 0

L = 2W
A = 50
A = L x W
50 = 2W x W
50 = 2W^2
W^2 = 25
W = 5
so L = 2W = 2(5) = 10

P = 2(L+W)
P = 2(10+5)
P = 2(15)
P = 30

answer
P = 30 in

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