Step-by-step explanation:
a.) the given term can be written as
=

=

=

hence the given term is

where b = 3
b.)
=

=

=

=

hence the given term is 12
Given Information:
Total cards = 108
Red cards = 25
yellow cards = 25
Blue cards = 25
Green cards = 25
Wild cards = 8
Required Information:
Probability that a hand will contain exactly two wild cards in a seven-hand game = ?
Answer:
P = (₈C₂*₁₀₀C₅)/₁₀₈C₇
Step-by-step explanation:
The required probability is given by
P = number of ways of interest/total number of ways
The total number of ways of dealing a seven-card hand is
₁₀₈C₇
We want to select exactly 2 wild cards and the total wild cards are 8 so the number of ways of this selection is
₈C₂
Since the game is seven-card hand, we have to get the number of ways to select remaining 5 cards out of (108 - 8 = 100) cards.
₁₀₀C₅
Therefore, the setup for this problem becomes
P = number of ways of interest/total number of ways
P = (₈C₂*₁₀₀C₅)/₁₀₈C₇
This is the required setup that we can type into our calculators to get the probability of exactly two wild cards in a seven-hand card game with 8 wild cards and 108 total cards.
Answer: 6.25
Step-by-step explanation:
Assuming that the ratios stay the same, the answer is going to be 6 because the total number of nuts drawn originally was 48, and 9 were cashews. To maintain this ratio when 32 nuts were drawn, the number of cashews will be 6.
There are 12 possible outcomes.....three of these will be a "7" ...so...
A "7" should occur 1/4 of the time
If each player pays 20p to play.....the school will take in 120 * 20 = 2400p
However.......1/4 of the players should win = 30 players.....and each lollipop costs 30p.....so......the school should spend 30 * 30 = 900p for the prizes
So......the school should raise 2400 - 900 = 1500p if 120 people play the game