Ask question

Ask question

All categories

3 years ago

10

The tourists went in the first hour with a speed of 3.5km/h to the bus station, realizing that they would arrive 1 hour late at

the bus station by moving so, they increased their speed by 1,5km/h and arrived now 30 min earlier. How long is the distance they walked?

1 answer:

mestny [16]3 years ago

7 0

The answer should be 4.25km

You might be interested in

3.Cornelia spends 2 2/3 hours studying for her big science test. She spent 2/3 of an hour finishing her writing assignment and 1

Nuetrik [128]

2 2/3 + 2/3 + 1/4 =
8/3 + 2/3 + 1/4 =
10/3 + 1/4 =
40/12 + 3/12 =
43/12 =
3 7/12 hrs <===

7 0

3 years ago

A light private plane can fly 120 mph in still air. Flying against the wind, the plane can fly 320 miles in the same time it req

TiliK225 [7]

A.<span>640/(120+w)
...............................................................................................................................................................................</span>

6 0

3 years ago

Read 2 more answers

This is for today someone help me?!!!!!

PolarNik [594]

I think that it’s 17 not a good

4 0

3 years ago

Read 2 more answers

A speed walker covered 4 1/2 mi in 3/4 hour. How far will he walk with the same pace in 3.5 hours?

alisha [4.7K]

Distance = Speed × Time

Distance = (4.5 mi)/(0.75 h) × (3.5 h) = 21 mi

The walker will cover 21 miles in 3.5 hours at that pace.

6 0

3 years ago

Read 2 more answers

I need help asap please

rjkz [21]

Answer:

$x = -\frac{3}{2}$ or $x = 1$

Step-by-step explanation:

Using the zero product property, first step is to set the given equation, $2x^2 + x - 1 = 2$ , to zero. Then factorise the left side.

Thus,

$2x^2 + x - 1 = 2$

Subtract 2 from both sides

$2x^2 + x - 1 - 2 = 2 - 2$

$2x^2 + x - 3 = 0$

Factorise the left side

$2x^2 + 3x - 2x - 3 = 0$

$x(2x + 3) - 1(2x + 3) = 0$

$(x - 1)(2x + 3) = 0$

Find the solution

$x - 1 = 0$

Or

$2x + 3 = 0$

$x = 1$

Or

$2x + 3 = 0$

$2x = -3$

$x = -\frac{3}{2}$

The answer is: $x = 1$ or $x = -\frac{3}{2}$

3 0

3 years ago