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3 years ago

This is for today someone help me?!!!!!

Mathematics

2 answers:

PolarNik [594]3 years ago

4 0

I think that it’s 17 not a good

lukranit [14]3 years ago

4 0

Angle m and r both equal 124
angle q and n both equal 56

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Please help me I think the answer is 12 cm .

-Dominant- [34]

You can find the value of the hypotenuse if you apply the Pythagorean Theorem, which is show below:

h²=a²+ b² ⇒ h=√(a² + b²)

h: hypotenuse (the opposite side of the right angle and the longest side of the triangle).

a and b: legs (the sides that form the right angle).

Then, you have:

h²=a² + b²

h²=12²+12²

h=√ ((12)² + (12)²)

h=12√2

What is the lenght of the hypotenuse?

The answer is: The length of the hypotenuse is 12√2

6 0

3 years ago

Find the measure of angle x in the figure below: A.) 35° B.) 48° C.) 69° D.) 78°

prisoha [69]

Answer:

x = 48

Step-by-step explanation:

First find y

52+y+59 = 180 since they from a straight line

y = 180-59-52

y = 69

Then we know the angles of a triangle add to 180

x+y+63 = 180

x+69+63 = 180

x = 180-69-63

x =48

3 0

3 years ago

Read 2 more answers

Evaluate the indicated function for f(x)=x2- 6 and g(x)=x+ 4. (fg (1)

Naily [24]

Answer:

I think that is going to be x-3

4 0

2 years ago

What is the best estimate for the product of 289 and seven

Shtirlitz [24]

The answer is 2023, so I would say 2000

3 0

3 years ago

Read 2 more answers

A tank initially has 300 gallons of a solution that contains 50 lb. of dissolved salt. A brine solution with a concentration of

belka [17]

Let s(t) be the amount of salt in the tank at time t. Then s(0) = 50 lb.

Salt flows into the tank at a rate of

(2 gal/min) (6 lb/gal) = 12 lb/min

and flows out at a rate of

(2 gal/min) (s(t)/300 lb/gal) = s(t)/150 lb/min

so that the net rate at which salt is exchanged through the tank is

ds(t)/dt = 12 - s(t)/150 … (lb/min)

Solve for s(t). The DE is separable, so we have

ds/dt = 12 - s/150

150 ds/dt = 1800 - s

150/(1800 - s) ds = dt

Integrate both sides to get

-150 ln|1800 - s| = t + C

Solve for s :

ln|1800 - s| = -t/150 + C

1800 - s = exp(-t/150 + C )

1800 - s = C exp(-t/150)

s = 1800 - C exp(-t/150)

Now given that s(0) = 50, we solve for C :

50 = 1800 - C exp(-0/150)

50 = 1800 - C

C = 1750

Then the amount of salt in the tank at any time t ≥ 0 is

s(t) = 1800 - 1750 exp(-t/150)

To find the time it takes for the tank to hold 100 lb of salt, solve for t in

100 = 1800 - 1750 exp(-t/150)

1700 = 1750 exp(-t/150)

34/35 = exp(-t/150)

ln(34/35) = -t/150

t = -150 ln(34/35) ≈ 4.348

So it would take approximately 4.348 minutes.

By the way, we didn't have to solve for s(t), we could have instead stopped with

-150 ln|1800 - s| = t + C

Solve for C - this C is not the same as the one we found using the other method. s(0) = 50, so

-150 ln|1800 - 50| = 0 + C

C = -150 ln|1750|

==> t = 150 ln(1750) - 150 ln|1800 - s|

Then s(t) = 100 lb when

t = 150 ln(1750) - 150 ln(1700)

t = 150 ln(1750/1700)

t = 150 ln(35/34)

t ≈ 4.348

5 0

3 years ago