V=x³-7x+6, V=(x-2)(x+3)*h
(x-2)(x+3)*h=x³-7x+6
h{x²+x-6}=x³-7x+6
h=(x³-7x+6)/(x²+x-6)
Therefore h=x-1
-----------------------------
Check answer:
V=(x-2)(x+3)(x-1)
=(x-1)(x²+x-6)
=x(x²+x-6)-1(x²+x-6)
=x³+x²-6x-x²-x+6
=x³-6x-x+6
=x³-7x+6
Okkk so u need to use the Pythagorean Theorum.

a=x
b=1
c=5
so...


Solve that
Answer:
6-2=4
31/5 x 8 = 248/40
15/8 x 5 = 75/40
248-75=173
4 13/40
answers in order
6-2=4
6 1/5 - 1 7/8 = 4 13/40
Hope this helps
Step-by-step explanation:
Answer:
Dude go to photomath
Step-by-step explanation:
It's easy
Answer:
A
Step-by-step explanation:
The equation of a parabola in vertex form is
y = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
Here (h, k) = (2, 1), thus
y = a(x - 2)² + 1
To find a substitute (1, 0) into the equation
0 = a(1 - 2)² + 1
0 = a + 1 ( subtract 1 from both sides )
a = - 1
Hence
y = - (x - 2)² + 1 or
y = 1 - (x - 2)² → A