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ivanzaharov [21]
3 years ago
9

A speed walker covered 4 1/2 mi in 3/4 hour. How far will he walk with the same pace in 3.5 hours?

Mathematics
2 answers:
jarptica [38.1K]3 years ago
7 0

21 miles is the answer

Hope this helped!!!!!!!!!

alisha [4.7K]3 years ago
6 0

Distance = Speed × Time

Distance = (4.5 mi)/(0.75 h) × (3.5 h) = 21 mi

The walker will cover 21 miles in 3.5 hours at that pace.

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Choose the correct simplification of (2x3 + x2 − 4x) − (9x3 − 3x2).
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You start off by multiplying the second bracket by -1 to get rid of the bracket.
So,
(2x3 + x2 - 4x) - 9x3 + 3x2 =
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(2x3 - 9x3) + (x2 + 3x2) - 4x =
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5. How many solutions will the following system of equations have?<br> y = -x +4<br> x² + y² = 16
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Answer:

x = 0 and y = 4

x = 4 and y = 0

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Step-by-step explanation:

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Susan bought a pair of jeans for $20.95 and a shirt for $11.50. She paid with $40.00. How much was her change?
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Suppose that the height (in centimeters) of a candle is a linear function of the amount of time (in hours) it has been burning.
natka813 [3]

Suppose that the height (in centimeters) of a candle is a linear function of

the amount of time (in hours) it has been burning.

Let x be the amount of time in hours

Let y be the heoght of a candle in centimeters

The two points are then as (9,24.5) and (23,17.5).

\mathrm{Find\:the\:line\:}\mathbf{y=mx+b}\mathrm{\:passing\:through\:}\left(9,\:24.5\right)\mathrm{,\:}\left(23,\:17.5\right)

\mathrm{Slope\:between\:two\:points}:\quad \mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(9,\:24.5\right),\:\left(x_2,\:y_2\right)=\left(23,\:17.5\right)

m=\frac{17.5-24.5}{23-9}

m=-0.5

\mathrm{Plug\:the\:slope\:}-0.5\mathrm{\:into\:}y=mx+b

y=\left(-0.5\right)x+b

\mathrm{Plug\:in\:}\left(9,\:24.5\right)\mathrm{:\:}\quad \:x=9,\:y=24.5

24.5=\left(-0.5\right)\cdot \:9+b

24.5=\left(-0.5\right)\cdot \:9+b

-4.5+b=24.5

b=29

\mathrm{Construct\:the\:line\:equation\:}\mathbf{y=mx+b}\mathrm{\:where\:}\mathbf{m}=-0.5\mathrm{\:and\:}\mathbf{b}=29

y=-0.5x+29

Now plug in x=21, we get

y=-0.5*21+29=18.5

Thus the height of the candle after 21 hours is 18.5 centimeters.

7 0
3 years ago
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