Question

Can someone simply this for me?

Answer 1

1/2 would be the correct answer

Answer 2

$\bf ~~~~~~~~~~~~\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} \qquad \qquad \cfrac{1}{a^n}\implies a^{-n} \qquad \qquad a^n\implies \cfrac{1}{a^{-n}}\\\\[-0.35em] \rule{34em}{0.25pt}\\\\ (3^3)(4^0)^2(3\cdot 2)^{-3}(2^2)\implies (27)(1)^2(6)^{-3}(4)\implies 27\cdot 1\cdot \cfrac{1}{6^3}\cdot 4\implies 108\cdot \cfrac{1}{216} \\\\\\ \cfrac{108}{216}\implies \cfrac{1}{2}$