Answer:
The answer in the procedure
Step-by-step explanation:
we have
2x-3y=-1 ----> equation A
3x+3y=26 --> equation B
Solve the system by elimination
Adds equation A and equation B
2x-3y=-1
3x+3y=26
----------------
2x+3x=-1+26
5x=25
x=25/5
x=5
Find the value of y
substitute the value of x in equation A or equation B and solve for y
2(5)-3y=-1
10-3y=-1
3y=10+1
y=11/3
Answer:
10
Step-by-step explanation:
I got you Gang (insert random gang signs that mean respect or something)
to find the area of a 2dimensional rectangle
we must use the formula
l × h = area
pretend that (5) means the square root of 5
(5) × 2(5) = 2(25)
simplify (25) = 5
2 × 5 = 10
A least common multiple should have all factors of the numbers, for which we want to know the least common multiple.
5 and 8 do not have common factors, so their common multiple is 5*8=40
Answer is 40.
Answer:
d. x = 5
Step-by-step explanation:
Chords that subtend congruent arcs are congruent.
<h3>Setup</h3>
Chord lengths are the same:
AB = CD
16x -2 = 14x +8
<h3>Solution</h3>
2x = 10 . . . . . . add 2-14x
x = 5 . . . . . . . . divide by 2
The range would be [-4, infinity) because range is the y-value. The lowest y-value is -4. The greatest y-value goes up to infinity.
