Let
be the inital number of Timmy's marbles, and
be the inital number of Ben's marbles.
At the beginning, "Timmy had 3/4 of what Ben had", which means
![t = \cfrac{3}{4}b \iff 4t=3b](https://tex.z-dn.net/?f=%20t%20%3D%20%5Ccfrac%7B3%7D%7B4%7Db%20%20%5Ciff%204t%3D3b)
(I wrote the equation in an equivalent form to avoid denominators)
Then, Ben gives 36 marbles to Timmy. So, now Ben has
marbles, and Timmy has
marbles. The new ratio is 1 to 3 in Timmy's favour, so we have
![b-36 = \cfrac{t+36}{3} \iff 3(b-36) = t+36 \iff 3b-108 = t+36](https://tex.z-dn.net/?f=%20b-36%20%3D%20%5Ccfrac%7Bt%2B36%7D%7B3%7D%20%5Ciff%203%28b-36%29%20%3D%20t%2B36%20%5Ciff%203b-108%20%3D%20t%2B36%20)
(same as before)
So, we have the following linear system:
![\begin{cases}4t=3b\\3b-108=t+36\end{cases}](https://tex.z-dn.net/?f=%20%5Cbegin%7Bcases%7D4t%3D3b%5C%5C3b-108%3Dt%2B36%5Cend%7Bcases%7D%20)
From the first equation we know that
, so the second equation becomes
![4t-108=t+36 \iff 3t = 144 \iff t = \cfrac{144}{3} = 48](https://tex.z-dn.net/?f=%204t-108%3Dt%2B36%20%5Ciff%203t%20%3D%20144%20%5Ciff%20t%20%3D%20%5Ccfrac%7B144%7D%7B3%7D%20%3D%2048%20)
Now that we know the value for
, we can simply plug it into the first equation to get
![3b = 4\times 48 = 192 \iff b=\cfrac{192}{3} = 64](https://tex.z-dn.net/?f=%203b%20%3D%204%5Ctimes%2048%20%3D%20192%20%5Ciff%20b%3D%5Ccfrac%7B192%7D%7B3%7D%20%3D%2064%20)
The ratios in a 30-60-90 triangle are 1 :
: 2. Therefore, since the hypotenuse is the longest and it is 10, 10 / 2 is 5 meaning 5 is the smallest side.
If it was asking for the amount that Chris made, the answer would be 18.
Hope this helps!<3
Answer: "less than" = subtract ( x - y )
So in this case its is 5-9 = -4 or 9-5=4.
Answer:
False
Step-by-step explanation:
I'm pretty sure it's false, sry if it's not