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kotegsom [21]
3 years ago
11

Kathy is changing the tire of her car on a steep hill 20m high. She trips and drops the 10kg spare tire which rolls down the hil

l. What is the speed of the tire at the top of the next hill if the height of the hill is 5m high?
Physics
1 answer:
Marrrta [24]3 years ago
4 0
For my answer to the question above, Let's assume that there is no friction.

The total energy E (kinetic + potential) of the tire is: 

<span>E = mv^2 / 2 + mgh </span>

<span>Since we're not given the tire's mass distribution or the hill's coefficient of friction or anything, assume we're to disregard rotational inertia, the energy dissipated as heat, etc. </span>

<span>Given that: </span>

<span>m = 10.0 kg </span>
<span>v0 = 2.0 m/s </span>
<span>h0 = 20.0 m </span>

<span>We're to find v when h = 5.0 m </span>

<span>Since the overall energy is conserved, </span>

<span>m(v0)^2 / 2 + mg(h0) = mv^2 / 2 + mgh </span>

<span>=> </span>

<span>v = sqrt((v0)^2 + 2g(h0 - h) </span>

<span>= sqrt( 4.0 m^2 / s^2 + (2)(9.8 m / s^2) (15.0 m) ) </span>

<span>= sqrt( 298 m^2 / s^2 ) </span>

<span>= 17.26 m/s</span>
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Answer:

4.662 slugs

Explanation:

Your mass on the moon should always be the same as any planet you are on (due to law of mass conservation), only your weight be different as gravitational acceleration is different on each planet.

If you weight 150 lbf on Earth, and gravitational acceleration on Earth is 32.174 ft/s2. The your mass on Earth is

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which is also your mass on the moon.

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3 years ago
A radar station sends out a 250000 Hz sound wave at a speed of 340 m/s. The sound wave bounces off a weather ballon and returns
Eddi Din [679]

Answers:

a)The balloon is 68 m away of the radar station

b) The direction of the balloon is towards the radar station

Explanation:

We can solve this problem with the Doppler shift equation:

f'=\frac{V+V_{o}}{V-V_{s}} f  (1)

Where:

f=250,000 Hz is the actual frequency of the sound wave

f'=240,000 Hz is the "observed" frequency

V=340 m/s is the velocity of sound

V_{o}=0 m/s is the velocity of the observer, which is stationary

V_{s} is the velocity of the source, which is the balloon

Isolating V_{s}:

V_{s}=\frac{V(f'-f)}{f'}  (2)

V_{s}=\frac{340 m/s(240,000 Hz-250,000 Hz)}{240,000 Hz}  (3)

V_{s}=-14.16 m/s (4) This is the velocity of the balloon, note the negative sign indicates the direction of motion of the balloon: It is moving towards the radar station.

Now that we have the velocity of the balloon (hence its speed, the positive value) and the time (t=4.8 s) given as data, we can find the distance:

d=V_{s}t (5)

d=(14.16 m/s)(4.8 s) (6)

Finally:

d=68 m (8) This is the distance of the balloon from the radar station

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3 years ago
Which sentence describe newton's third law?
strojnjashka [21]
C. Forces are always in pairs
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Which of the following solar oven design materials would serve as the best insulator to minimize the transfer of thermal energy
love history [14]

Answer:

layers of cotton lining the interior

Explanation:

5 0
3 years ago
A point charge Q is held at a distance r from the center of a dipole that consists of two charges ±q separated by a distance s.
marishachu [46]

Answer:

a) the magnitude of the force is

F= Q(\frac{kqs}{r^3}) and where k = 1/4πε₀

F = Qqs/4πε₀r³

b)  the magnitude of the torque on the dipole

τ = Qqs/4πε₀r²

Explanation:

from coulomb's law

E = \frac{kq}{r^{2} }

where k = 1/4πε₀

the expression of the electric field due to dipole at a distance r is

E(r) = \frac{kp}{r^{3} } , where p = q × s

E(r) = \frac{kqs}{r^{3} } where r>>s

a) find the magnitude of force due to the dipole

F=QE

F= Q(\frac{kqs}{r^3})

where k = 1/4πε₀

F = Qqs/4πε₀r³

b) b) magnitude of the torque(τ) on the dipole is dependent on the perpendicular forces

τ = F sinθ × s

θ = 90°

note: sin90° = 1

τ = F × r

recall  F = Qqs/4πε₀r³

∴ τ = (Qqs/4πε₀r³) × r

τ = Qqs/4πε₀r²

8 0
3 years ago
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