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3 years ago

Which sentence describe newton's third law?

Physics

1 answer:

strojnjashka [21]3 years ago

3 0

C. Forces are always in pairs

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A vacuum cleaner produces sound with a measured sound level of 75.0 dB. (a) What is the intensity of this sound in W/m2? W/m2 (b

jonny [76]

Answer:

Part a)

$I = 3.16 \times 10^{-5} W/m^2$

Part b)

$P_o = 0.162 Pa$

Explanation:

Part a)

Level of sound = 75 dB

now we know that

$L = 10 Log\frac{I}{I_0}$

here we know that

$I_0 = 10^{-12} W/m^2$

now we have

$75 = 10 Log(\frac{I}{10^{-12}})$

$I = 3.16 \times 10^{-5} W/m^2$

Part b)

Intensity of sound wave is given as

$I = \frac{1}{2}\rho A^2\omega^2 c$

here we know that

$A = \frac{P_o}{Bk}$

so we have

$I = \frac{1}{2}\rho(\frac{P_o}{Bk})^2\omega^2 c$

$I = \frac{1}{2}\rho P_o^2 \frac{c^3}{B^2}$

now we know

$\rho = 1.2 kg/m^3$

$c = 340 m/s$

$B = 1.4 \times 10^5 Pa$

now we have

$3.16 \times 10^{-5} = \frac{1}{2}(1.2)P_o^2\frac{340^3}{(1.4\times 10^5)^2}$

$P_o = 0.162 Pa$

5 0

3 years ago

A 5.0-cm by 7.0-cm rectangular coil has 100 turns. Its axis makes an angle of 65° with a uniform magnetic field of 0.55 T. What

kotegsom [21]

Answer:

0.0814 Wb

Explanation:

L = length of the rectangular coil = 5 cm = 0.05 m

w = width of rectangular coil = 7 cm = 0.07 m

A = Area of the coil = L w = 0.05 x 0.07 = 35 x 10⁻⁴ m²

B = magnitude of uniform magnetic field = 0.55 T

θ = angle of axis of coil with magnetic field = 65°

Magnetic flux through the coil is given as

Φ = N B A Cosθ

Φ = (100) (0.55) (35 x 10⁻⁴ ) Cos65

Φ = 0.0814 Wb

4 0

4 years ago

How long will it take a person walking at 3.2 m/s to travel 16 m? *

BigorU [14]

Answer:

speed=distance/time

time=distance/speed

time=16/3.2

time=5 seconds

time will take 5 seconds

3 0

3 years ago

The force between two objects, each of charge +Q is measured as +F when the objects are separated a distance d apart. If the cha

dybincka [34]

Answer:

$F'=4F$

Explanation:

According to Coulomb's law, the magnitude of the force (F) between two objects with the same charge(+Q), separated a distance (d) apart, is defined as:

$F=\frac{kQ^2}{d^2}$

Here k is the Coulomb constant. The charge on each object is doubled, that is $Q'=2Q$ :

$F'=\frac{kQ'^2}{d^2}\\F'=\frac{k(2Q)^2}{d^2}\\F'=4\frac{kQ^2}{d^2}\\F'=4F$

5 0

4 years ago

Which algebraic rule describes the transformation?

Paraphin [41]

Answer:

(y) - (x - 2, y + 5)

Explanation:

7 0

3 years ago