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Lisa [10]
3 years ago
5

Your clothing tends to cling together after going through the dryer. Why? Would you expect more or less clinging if all your clo

thing were made of the same material (say, cotton) than if you dried different kinds of clothing together? Again, why? (You may want to experiment with your next load of laundry.)
Physics
1 answer:
lys-0071 [83]3 years ago
4 0

Answer and Explanation:

The clothing after spinning in the dryer cling together. This is because in the dryer they are rubbed against each other and due to this rubbing, electrons are transferred from one to the other clothes and acquire charge as a result of charging by friction thus producing static electricity.

As the material of the clothes in the dryer is different, clinging will be more.

The sticking of these clothes together is known as Static cling.

In case, the clothing are of same material, the static electricity produced as a result of frictional charging would be less and hence less static cling would occur.

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Help me please Am I correct???​
trasher [3.6K]

Answer:

They both experienced the same force as they weigh the same amount

Newtonian physics

Explanation:

5 0
3 years ago
Big Al stands on a skateboard at a rest and throws a 0.5-kilogram rock at a velocity of 10.0 m /sec. Big Al moves back at 0.05 m
Vlada [557]
Let
his and skateboard's combined mass is x
we know
F1=-F2
0.5kg*10m/s=-0.05m/s xkg
5=0.05x(minus cancel with the m/s as it represented the opposite direction of velocity and now there is no velocity in this equation.. so minus is avoidable. and the kgs cancel out)
x=10
so their combined mass is a 100 kg.. (I hope I didn't mess thing up for you)
4 0
3 years ago
A viscous liquid is sheared between two parallel disks of radius �, one of which rotates with angular speed Ω, while the other i
Alexus [3.1K]

Answer:

Upper disk rotates at a constant angular velocity. The velocity at any height from stationery disk, say at x metres

U_o=v(\frac {x}{h}) where v is tangential velocity at radius r from the centre of disk

U_o=r\omega (\frac {x}{h})

The radial component of velocity is given as

U_r=0

The z component of velocity is also given as  

W=0

Total velocity, v= r\omega (\frac {x}{h})\hat e_{o}

5 0
3 years ago
Help me! Btw he’s playing golf.
fiasKO [112]

Answer:

Muscular energy

Explanation:

Hope it helps!!!!

5 0
3 years ago
PLEASE NEED THIS QUICKLY
saw5 [17]

The potential energy of the block is A) 490 J

Explanation:

The potential energy of an object is the energy possessed by the object due to its position in the gravitational field.

It is calculated as follows:

PE=mgh

where

m is the mass of the object

g is the acceleration due to gravity

h is the height of the object above the ground

For the block in this problem, we have:

m = 10 kg

g=9.8 m/s^2

h = 5 m

Therefore, its potential energy is:

PE=(10)(9.8)(5)=490 J

Learn more about potential energy:

brainly.com/question/1198647

brainly.com/question/10770261

#LearnwithBrainly

3 0
3 years ago
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