Ask question

Ask question

All categories

3 years ago

7

Please explain what the answer is.

1 answer:

Zolol [24]3 years ago

3 0

21Answer:21

Step-by-step explanation:

You might be interested in

A new television set was recently purchased for a common room in a residence hall for $408.00 including tax. If the tax rate is

Nadusha1986 [10]

Answer:

$400

Step-by-step explanation:

To solve this, we need to understand how one reaches the final price. The general formula for final price (with tax) is:

t(c) = p x (1+t)

t(c) is total cost

p is price

t is tax rate as a decimal

To find p, we need to create a new formula. Since we have the total cost ($408) and the tax rate (2% or .02), we can divide the total cost by 1 + the tax rate to solve for the price:

t(c) / (1+t) = p

408 / (1+.02) = $400

I hope this helps!

-TheBusinessMan

7 0

4 years ago

A room has an area of 60 square meters and a perimeter of 32 meters what are the length and width of the room

kupik [55]

We can solve this by looking at pairs that equal 60.
6 and 10 get to 60 when multiplied. Let's see if it fits in as a perimeter.
12+20=32
So the width and length of the room is 6 meters and 10 meters.

5 0

3 years ago

Christopher is thinking of two positive integers. The sum of the integers is 27. When twice the first integer is added to half o

LenKa [72]

Answer:

Let x and y be the two positive integers the Christopher is thinking.

x is equal to 7

and y =20

8 0

3 years ago

A rectangular box with a volume of 272ft^3 is to be constructed with a square base and top. The cost per square foot for the bot

ASHA 777 [7]

Answer:

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

The length of one side of the base of the given box is 3 ft.

The height of the box is 30.22 ft.

Step-by-step explanation:

Given that, a rectangular box with volume of 272 cubic ft.

Assume height of the box be h and the length of one side of the square base of the box is x.

Area of the base is = $(x\times x)$

$=x^2$

The volume of the box is = area of the base × height

$=x^2h$

Therefore,

$x^2h=272$

$\Rightarrow h=\frac{272}{x^2}$

The cost per square foot for bottom is 20 cent.

The cost to construct of the bottom of the box is

=area of the bottom ×20

$=20x^2$ cents

The cost per square foot for top is 10 cent.

The cost to construct of the top of the box is

=area of the top ×10

$=10x^2$ cents

The cost per square foot for side is 1.5 cent.

The cost to construct of the sides of the box is

=area of the side ×1.5

$=4xh\times 1.5$ cents

$=6xh$ cents

Total cost = $(20x^2+10x^2+6xh)$

$=30x^2+6xh$

Let

C $=30x^2+6xh$

Putting the value of h

$C=30x^2+6x\times \frac{272}{x^2}$

$\Rightarrow C=30x^2+\frac{1632}{x}$

Differentiating with respect to x

$C'=60x-\frac{1632}{x^2}$

Again differentiating with respect to x

$C''=60+\frac{3264}{x^3}$

Now set C'=0

$60x-\frac{1632}{x^2}=0$

$\Rightarrow 60x=\frac{1632}{x^2}$

$\Rightarrow x^3=\frac{1632}{60}$

$\Rightarrow x\approx 3$

Now $C''|_{x=3}=60+\frac{3264}{3^3}>0$

Since at x=3 , C''>0. So at x=3, C has a minimum value.

The length of one side of the base of the box is 3 ft.

The height of the box is $=\frac{272}{3^2}$

=30.22 ft.

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

7 0

3 years ago

Myles's school is selling tickets to an end of the year

dusya [7]

Answer:

about 13$ and 6 cents

Step-by-step explanation:

5 0

3 years ago